예제 #1
0
 /// <summary>
 /// Initialises the solution and associates it with a specified problem.
 /// </summary>
 /// <param name="problem">The problem to associate this solution with</param>
 public Solution(Problem problem)
 {
     this.problem = problem;
     cowboys = new Cowboy[Problem.NumCowboys];
     for (int i = 0; i < Problem.NumCowboys; i++)
     {
         cowboys[i] = new Cowboy(problem);
     }
     checkCowboys();
 }
예제 #2
0
파일: Cowboy.cs 프로젝트: OCox1991/Cowboys
 /// <summary>
 /// Sorts the cowboys by if they are alive or not
 /// </summary>
 /// <param name="negCowboy">The cowboy that gives a -1 response if it is alive and the other isn't</param>
 /// <param name="posCowboy">The cowboy that gives a 1 response if it is alive and the other isn't</param>
 /// <returns>-1 or 1 if one cowboy is alive and the other isnt 0 otherwise</returns>
 public static int sortAlive(Cowboy negCowboy, Cowboy posCowboy)
 {
     negCowboy.problem.compare();
     int ret = 0;
     if ((negCowboy.isDead && posCowboy.isDead) || (!negCowboy.isDead && !posCowboy.isDead))
     {
     }
     else if (negCowboy.isDead && !posCowboy.isDead)
     {
         ret = 1;
     }
     else if (posCowboy.isDead && !negCowboy.isDead)
     {
         ret = -1;
     }
     return ret;
 }
예제 #3
0
파일: Problem.cs 프로젝트: OCox1991/Cowboys
 /// <summary>
 /// Breeds a new cowboy with the specified parents.
 /// </summary>
 /// <param name="c1">The first parent of the new cowboy</param>
 /// <param name="c2">The second parent of the new cowboy</param>
 /// <returns>The cowboy that is the offspring of the 2 parent cowboys provided</returns>
 public Cowboy breedNewCowboy(Cowboy c1, Cowboy c2)
 {
     return new Cowboy(this, new decimal[] { c1.Location[0], c2.Location[1] });
 }
예제 #4
0
파일: Problem.cs 프로젝트: OCox1991/Cowboys
 /// <summary>
 /// Breeds a new cowboy selecting the parents randomly from a specified list
 /// </summary>
 /// <param name="cowboysList">The list of cowboys that are potential parents for the new cowboy</param>
 /// <returns>A new cowboy bred from 2 random parents in the provided list</returns>
 public Cowboy breedNewCowboy(Cowboy[] cowboysList)
 {
     if (Random.Next(MutationChance) == 0)
     {
         return new Cowboy(this);
     }
     else
     {
         Cowboy cb1 = cowboysList[Random.Next(cowboysList.Length)];
         Cowboy cb2 = cowboysList[Random.Next(cowboysList.Length)];
         return (breedNewCowboy(cb1, cb2));
     }
 }
예제 #5
0
 /// <summary>
 /// Initialises the solution providing it the list of cowboys and the problem to
 /// be associated with
 /// </summary>
 /// <param name="problem">The problem to associate this solution with</param>
 /// <param name="cowboys">The list of cowboys to use for this solution</param>
 public Solution(Problem problem, Cowboy[] cowboys)
 {
     this.problem = problem;
     this.cowboys = cowboys;
     checkCowboys();
 }
예제 #6
0
파일: Cowboy.cs 프로젝트: OCox1991/Cowboys
 /// <summary>
 /// Returns the better cowboy based on the visibility of the cowboy, with better
 /// cowboys having lower visibility.
 /// </summary>
 /// <param name="posCowboy">The cowboy that if better will get the return value 1</param>
 /// <param name="negCowboy">The cowboy that if better will get the return value -1</param>
 /// <returns>1 if posCowboy is better, -1 if negCowboy is better and 0 if they are equal</returns>
 public static int sortByNumSeen(Cowboy negCowboy, Cowboy posCowboy)
 {
     posCowboy.problem.compare();
     if (posCowboy.NumSeen < negCowboy.NumSeen)
     {
         return 1;
     }
     else if (posCowboy.NumSeen > negCowboy.NumSeen)
     {
         return -1;
     }
     else //if posCowboy.NumSeen == negCowboy.NumSeen
     {
         return 0;
     }
 }
예제 #7
0
파일: Cowboy.cs 프로젝트: OCox1991/Cowboys
 /// <summary>
 /// Sorts the cowboys by location, with top left being placed first
 /// </summary>
 /// <param name="negCowboy">The cowboy which will elicit a -1 response if it is found to be more NW than the other</param>
 /// <param name="posCowboy">The cowboy which will elicit a 0 response if it is found to be more NW than the other</param>
 /// <returns>-1 or 1 depending on which cowboy is the furthest NW or 0 if they are equal</returns>
 public static int sortByLocation(Cowboy negCowboy, Cowboy posCowboy)
 {
     negCowboy.problem.compare();
     decimal[] negLoc = negCowboy.Location;
     decimal[] posLoc = posCowboy.Location;
     if (negLoc[1] < posLoc[1])
     {
         return -1;
     }
     else if (negLoc[1] > posLoc[1])
     {
         return 1;
     }
     else
     {
         if (negLoc[0] < posLoc[0])
         {
             return -1;
         }
         else if (negLoc[0] > posLoc[0])
         {
             return 1;
         }
         else
         {
             return 0;
         }
     }
 }