void ExecuteOpenFile(object param) { switch (param) { case "Work": CurrentApp.WorkingReleasePath = MainModel.FindPath(); break; case "Release": CurrentApp.ReleasePath = MainModel.FindPath(); break; case "Reestr": CurrentApp.ReestrPath = MainModel.FindPath(); break; } }
void ExecuteOpenFolderDialog() { FileName = MainModel.FindPath() + System.IO.Path.DirectorySeparatorChar + "Apps.XML"; }