public void Test_Tri() { List <double> list = new List <double>(); list.Add(20); list.Add(201); list.Add(11); list.Add(5); list.Add(44); list.Add(-12); CollectionAssert.AreEqual(Trier.Tri2(ref list), list); }
/** Adds a word into the data structure. */ public void AddWord(string word) { Trier tn = root; for (int i = 0; i < word.Length; i++) { char c = word[i]; if (tn.children[c - 'a'] == null) { tn.children[c - 'a'] = new Trier(); } tn = tn.children[c - 'a']; } tn.isWord = true; }
private bool SearchHelper(string word, int start, Trier curr) { if (start == word.Length) { if (curr.isWord) { return(true); } else { return(false); } } char c = word[start]; if (c == '.') { for (int i = 0; i < 26; i++) { if (curr.children[i] != null) { if (SearchHelper(word, start + 1, curr.children[i])) { return(true); } } } } else { if (curr.children[c - 'a'] == null) { return(false); } else { return(SearchHelper(word, start + 1, curr.children[c - 'a'])); } } return(false); }
public WordDictionary() { root = new Trier(); }
/** Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter. */ public bool Search(string word) { Trier currNode = root; return(SearchHelper(word, 0, currNode)); }
public Hello() { trier = new Trier (); }
public Hello() { trier = new Trier(); }