public void TestPermutationFactorTrendAnalyseResult_One_And_Two_Element()
{
var fac1 = new Factor <int> {
Left = new List <int> {
1, 2
}, Right = new List <int> {
3, 4
}
};
var fac2 = new Factor <int> {
Left = new List <int> {
5, 6
}, Right = new List <int> {
7, 8
}
};
var ls1 = new List <Factor <int> > {
fac1
};
var ls = new List <Factor <int> > {
fac1, fac2
};
var lss = new List <List <Factor <int> > > {
ls1, ls
};
var result = PermutationFactorTrend.TraversePermutationFactor(lss);
Assert.IsTrue(result.Count == 2 * 4);
}
public void TestAnalyse_Empty()
{
var numbers = new List <byte>
{
1, 3, 6, 9, 1, 4, 2, 3, 1, 2, 5, 6, 8, 2, 3, 1
};
var fac1 = new Factor <byte> {
Left = new List <byte> {
1, 2
}, Right = new List <byte> {
3, 4
}
};
var fac2 = new Factor <byte> {
Left = new List <byte> {
5, 6
}, Right = new List <byte> {
7, 8
}
};
//var fac3 = new Factor<byte> { Left = new List<byte> { 1, 2 }, Right = new List<byte> { 3, 4 } };
var permutationFactors = new List <Factor <byte> > {
fac1, fac2
};
var result = new PermutationFactorTrend().Analyse(new PermutationFactorTrendAnalyseDto <byte>
{
Numbers = numbers,
PermutationFactors = permutationFactors,
NumbersTailCutCount = 6
});
}
public void TestCountConsecutive()
{
var numbers = new List <byte>
{
1, 3, 6, 9, 1, 4, 2, 3, 1, 2, 5, 6, 8, 2, 3, 1
};
/*
* 索引位置： 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
* 号码列表： 1, 3, 6, 9, 1, 4, 2, 3, 1, 2, 5, 6, 8, 2, 3, 1
* 连续次数： 1 0 0 1 2 0 0 0 0 0 1 0
* 最大间隔： -1 X X 0 -1 X X X X X 1 X
*
*/
var factors = new List <List <byte> >
{
new List <byte> {
1, 2
},
new List <byte> {
3, 4
}
};
var predictiveFactor = new List <byte> {
5, 6
};
var cutCount = 6;
var result = PermutationFactorTrend.CountConsecutiveDistribution(numbers, factors, predictiveFactor);
//有两个连续次数
Assert.IsTrue(result.HistoricalConsecutiveTimes.Count == 2);
//连续次数＝1出现一次
Assert.IsTrue(result.HistoricalConsecutiveTimes[1] == 2);
//连续次数＝2出现一次
Assert.IsTrue(result.HistoricalConsecutiveTimes[2] == 1);
numbers = new List <byte>
{
1, 3, 9, 1, 3, 1, 3, 1, 3, 6, 9, 1, 4, 2, 3, 1, 4, 5, 6, 8, 2, 3, 1
};
result = PermutationFactorTrend.CountConsecutiveDistribution(numbers, factors, predictiveFactor);
//有两个连续次数
Assert.IsTrue(result.HistoricalConsecutiveTimes.Count == 2);
//连续次数＝1出现一次
Assert.IsTrue(result.HistoricalConsecutiveTimes[1] == 2);
//连续次数＝3出现2次
Assert.IsTrue(result.HistoricalConsecutiveTimes[3] == 2);
numbers = new List <byte>
{
1, 3, 9, 1, 3, 1, 3, 1, 3, 6, 9, 1, 4, 2, 3, 1, 4, 1, 4, 2, 3, 1, 4, 1, 4, 2, 3, 1, 4, 5, 6, 8, 2, 3, 1
};
result = PermutationFactorTrend.CountConsecutiveDistribution(numbers, factors, predictiveFactor);
//有3个连续次数
Assert.IsTrue(result.HistoricalConsecutiveTimes.Count == 3);
//连续次数＝1出现一次
Assert.IsTrue(result.HistoricalConsecutiveTimes[1] == 2);
//连续次数＝3出现一次
Assert.IsTrue(result.HistoricalConsecutiveTimes[3] == 1);
//连续次数＝9出现一次
Assert.IsTrue(result.HistoricalConsecutiveTimes[9] == 1);
}
