C# (CSharp) OpenImagDlg.ShowDialog 예제들

예제 #1

        private void button3_Click(object sender, EventArgs e)
        {
            if (OpenImagDlg.ShowDialog() == DialogResult.OK)

            {
                pictureBox1.Image = Image.FromFile(OpenImagDlg.FileName);
            }
        }

예제 #2

파일: Form3.cs 프로젝트: lix4000/DERID

        private void button4_Click(object sender, EventArgs e)
        {
            if (OpenImagDlg.ShowDialog() == DialogResult.OK)

            {
                pictureBox4.Image = Image.FromFile(OpenImagDlg.FileName);
                button6.Enabled   = true;
            }
        }