/// <summary>This returns a smooth point between the previous and current screen position based on a 0..1 progress value.</summary>
public Vector2 GetSmoothScreenPosition(float t)
{
if (Snapshots.Count > 0 && Set == true)
{
var d = Snapshots[Mathf.Max(0, Snapshots.Count - 4)].ScreenPosition;
var c = Snapshots[Mathf.Max(0, Snapshots.Count - 3)].ScreenPosition;
var b = Snapshots[Mathf.Max(0, Snapshots.Count - 2)].ScreenPosition;
var a = Snapshots[Mathf.Max(0, Snapshots.Count - 1)].ScreenPosition;
return(LeanHelper.Hermite(d, c, b, a, t));
}
return(Vector2.LerpUnclamped(LastScreenPosition, ScreenPosition, t));
}
