public ActionResult Edit(Guid id)
        {
            var technology = technologyService.Find(id);

            if (technology == null)
            {
                return(HttpNotFound());
            }
            return(View(technology));
        }
예제 #2
0
        public ActionResult Tags(string query)
        {
            var list = _technologyService.Find(query).ToArray();

            return(new JsonNetResult(list, HttpStatusCode.OK));
        }