//验证 第三种：需要回答验证问题的
static bool FriendTest3(AutomationElement appElement, bool next)
{
AutomationElement element = null;
AutomationElementCollection item = appElement.FindAll(TreeScope.Descendants,
new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC371));
for (int i = 0; i < item.Count; ++i)
{
AutomationElement tmp = item[i].FindFirst(TreeScope.Children,
new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC364));
if (tmp != null)
{
string name = tmp.Current.Name;
if (name.Contains("对方需要你回答") && name.Contains("个验证问题"))
{
AutomationElementCollection item2 = item[i].FindAll(TreeScope.Descendants,
new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC364));
for (int j = 0; j < item2.Count; ++j)
{
LegacyIAccessiblePattern pattern =
(LegacyIAccessiblePattern)item2[j].GetCurrentPattern(LegacyIAccessiblePattern.Pattern);
if (pattern != null && pattern.Current.Name.Contains("问题") && !pattern.Current.Name.Contains("对方需要你回答"))
{
AddFriInfo.add(pattern.Current.Name, name, 1);
}
}
element = item[i];
break;
}
}
}
return(element != null);
}
//身份验证窗口
//验证 第一种：需要输入正确答案的（放弃吧）
static bool FriendTest1(AutomationElement appElement)
{
AutomationElementCollection item = appElement.FindAll(TreeScope.Descendants,
new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC371));
for (int i = 0; i < item.Count; ++i)
{
Condition[] condition = new Condition[2];
condition[0] = new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC364);
condition[1] = new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC355);
AutomationElement element = item[i].FindFirst(TreeScope.Children, new OrCondition(condition));
if (element != null)
{
string key = element.Current.Name;
if (key == "对方需要你回答一下验证问题:" ||
key == "对方拒绝被添加" ||
key.Contains("已经是你的好友，不能重复添加"))
{
AutomationElementCollection item2 = item[i].FindAll(TreeScope.Descendants,
new PropertyCondition(AutomationElement.ControlTypeProperty, 0xC364));
for (int j = 0; j < item2.Count; ++j)
{
LegacyIAccessiblePattern pattern =
(LegacyIAccessiblePattern)item2[j].GetCurrentPattern(LegacyIAccessiblePattern.Pattern);
if (pattern != null && pattern.Current.ChildId == 2)
{
AddFriInfo.add(pattern.Current.Name, key, 2);
break;
}
}
return(true);
}
}
}
return(false);
}