public static async Task <bool> OpenInput(string inputDeviceName)
{
var inputInfo = AvailableInputDevices.SingleOrDefault(i => i.Name.ToLower() == inputDeviceName.ToLower());
if (inputInfo == default)
{
return(false);
}
ActiveInputDevices[inputDeviceName] = new MidiInputDevice(await AccessManager.OpenInputAsync(inputInfo.Id));
Logger.WriteLine("Successfully opened input device {0}", inputDeviceName);
return(true);
}
