ComparePosition() public method

Compare the relative positions of two navigators. Return -1 if navThis is before navThat, 1 if after, and 0 if they are positioned to the same node.
public ComparePosition ( XPathNavigator navigatorThis, XPathNavigator navigatorThat ) : int
navigatorThis System.Xml.XPath.XPathNavigator
navigatorThat System.Xml.XPath.XPathNavigator
return int
コード例 #1
0
        /// <summary>
        /// Insert the specified sequence into the list of sequences to be merged.
        /// Insert it in reverse document order with respect to the current nodes in other sequences.
        /// </summary>
        private void InsertSequence(IEnumerator <XPathNavigator> sequence)
        {
            for (int i = _sequencesToMerge.Count - 1; i >= 0; i--)
            {
                int cmp = _runtime.ComparePosition(sequence.Current, _sequencesToMerge[i].Current);

                if (cmp == -1)
                {
                    // Insert after current item
                    _sequencesToMerge.Insert(i + 1, sequence);
                    return;
                }
                else if (cmp == 0)
                {
                    // Found duplicate, so skip the duplicate
                    if (!sequence.MoveNext())
                    {
                        // No more nodes, so don't insert anything
                        return;
                    }

                    // Next node must be after current node in document order, so don't need to reset loop
                }
            }

            // Insert at beginning of list
            _sequencesToMerge.Insert(0, sequence);
        }
コード例 #2
0
ファイル: SetIterators.cs プロジェクト: mikem8361/runtime
        /// <summary>
        /// Position this iterator to the next node in the union.
        /// </summary>
        public SetIteratorResult MoveNext(XPathNavigator nestedNavigator)
        {
            switch (_state)
            {
            case IteratorState.InitLeft:
                // Fetched node from left iterator, now get initial node from right iterator
                _navLeft = nestedNavigator;
                _state   = IteratorState.NeedRight;
                return(SetIteratorResult.InitRightIterator);

            case IteratorState.NeedLeft:
                _navLeft = nestedNavigator;
                break;

            case IteratorState.NeedRight:
                _navRight = nestedNavigator;
                break;

            case IteratorState.NeedLeftAndRight:
                // After fetching left node, still need right node
                _navLeft = nestedNavigator;
                _state   = IteratorState.NeedRight;
                return(SetIteratorResult.NeedRightNode);

            case IteratorState.HaveCurrent:
                // Just returned left node as current, so fetch new left node
                Debug.Assert(nestedNavigator == null, "null is passed to MoveNext after IteratorState.HaveCurrent has been returned.");
                _state = IteratorState.NeedLeft;
                return(SetIteratorResult.NeedLeftNode);
            }

            if (_navLeft == null)
            {
                // If navLeft is null, then difference operation is complete
                return(SetIteratorResult.NoMoreNodes);
            }
            else if (_navRight != null)
            {
                int order = _runtime.ComparePosition(_navLeft, _navRight);

                // If navLeft is positioned to same node as navRight,
                if (order == 0)
                {
                    // Skip navLeft and navRight
                    _state = IteratorState.NeedLeftAndRight;
                    return(SetIteratorResult.NeedLeftNode);
                }

                // If navLeft is after navRight in document order, then skip navRight
                if (order > 0)
                {
                    _state = IteratorState.NeedRight;
                    return(SetIteratorResult.NeedRightNode);
                }
            }

            // Return navLeft
            _state = IteratorState.HaveCurrent;
            return(SetIteratorResult.HaveCurrentNode);
        }
コード例 #3
0
ファイル: SetIterators.cs プロジェクト: mikem8361/runtime
        /// <summary>
        /// Position this iterator to the next node in the union.
        /// </summary>
        public SetIteratorResult MoveNext(XPathNavigator nestedNavigator)
        {
            int order;

            switch (_state)
            {
            case IteratorState.InitLeft:
                // Fetched node from left iterator, now get initial node from right iterator
                _navLeft = nestedNavigator;
                _state   = IteratorState.NeedRight;
                return(SetIteratorResult.InitRightIterator);

            case IteratorState.NeedLeft:
                _navLeft = nestedNavigator;
                break;

            case IteratorState.NeedRight:
                _navRight = nestedNavigator;
                break;

            case IteratorState.NeedLeftAndRight:
                // After fetching left node, still need right node
                _navLeft = nestedNavigator;
                _state   = IteratorState.NeedRight;
                return(SetIteratorResult.NeedRightNode);

            case IteratorState.HaveCurrent:
                // Just returned left node as current, so fetch new left and right nodes
                Debug.Assert(nestedNavigator == null, "null is passed to MoveNext after IteratorState.HaveCurrent has been returned.");
                _state = IteratorState.NeedLeftAndRight;
                return(SetIteratorResult.NeedLeftNode);
            }

            if (_navLeft == null || _navRight == null)
            {
                // No more nodes from either left or right iterator (or both), so iteration is complete
                return(SetIteratorResult.NoMoreNodes);
            }

            // Intersect left and right sets
            order = _runtime.ComparePosition(_navLeft, _navRight);

            if (order < 0)
            {
                // If navLeft is positioned to a node that is before navRight, skip left node
                _state = IteratorState.NeedLeft;
                return(SetIteratorResult.NeedLeftNode);
            }
            else if (order > 0)
            {
                // If navLeft is positioned to a node that is after navRight, so skip right node
                _state = IteratorState.NeedRight;
                return(SetIteratorResult.NeedRightNode);
            }

            // Otherwise, navLeft is positioned to the same node as navRight, so found one item in the intersection
            _state = IteratorState.HaveCurrent;
            return(SetIteratorResult.HaveCurrentNode);
        }
コード例 #4
0
ファイル: SetIterators.cs プロジェクト: mikem8361/runtime
        /// <summary>
        /// Position this iterator to the next node in the union.
        /// </summary>
        public SetIteratorResult MoveNext(XPathNavigator nestedNavigator)
        {
            switch (_state)
            {
            case IteratorState.InitLeft:
                // Fetched node from left iterator, now get initial node from right iterator
                _navOther = nestedNavigator;
                _state    = IteratorState.NeedRight;
                return(SetIteratorResult.InitRightIterator);

            case IteratorState.NeedLeft:
                _navCurr = nestedNavigator;
                _state   = IteratorState.LeftIsCurrent;
                break;

            case IteratorState.NeedRight:
                _navCurr = nestedNavigator;
                _state   = IteratorState.RightIsCurrent;
                break;

            case IteratorState.LeftIsCurrent:
                // Just returned left node as current, so get new left
                _state = IteratorState.NeedLeft;
                return(SetIteratorResult.NeedLeftNode);

            case IteratorState.RightIsCurrent:
                // Just returned right node as current, so get new right
                _state = IteratorState.NeedRight;
                return(SetIteratorResult.NeedRightNode);
            }

            // Merge left and right nodes
            if (_navCurr == null)
            {
                // If both navCurr and navOther are null, then iteration is complete
                if (_navOther == null)
                {
                    return(SetIteratorResult.NoMoreNodes);
                }

                Swap();
            }
            else if (_navOther != null)
            {
                int order = _runtime.ComparePosition(_navOther, _navCurr);

                // If navCurr is positioned to same node as navOther,
                if (order == 0)
                {
                    // Skip navCurr, since it is a duplicate
                    if (_state == IteratorState.LeftIsCurrent)
                    {
                        _state = IteratorState.NeedLeft;
                        return(SetIteratorResult.NeedLeftNode);
                    }

                    _state = IteratorState.NeedRight;
                    return(SetIteratorResult.NeedRightNode);
                }

                // If navOther is before navCurr in document order, then swap navCurr with navOther
                if (order < 0)
                {
                    Swap();
                }
            }

            // Return navCurr
            return(SetIteratorResult.HaveCurrentNode);
        }