private static void AddItemsInList(SumList firstList, SumList secondList)
{
var sl3 = new SumList();
var power = 0;
//sl3.
int firstListSum = 0, secondListSum = 0;
if (firstList.listCount == secondList.listCount)
{
var currentNode = firstList.head;
while (currentNode != null)
{
firstListSum += currentNode.Value * Convert.ToInt32(Math.Pow(10, power));
currentNode = currentNode.Next;
power++;
//firstListSum += firstList.;
}
currentNode = secondList.head;
power = 0;
while (currentNode != null)
{
secondListSum += currentNode.Value * Convert.ToInt32(Math.Pow(10, power));
currentNode = currentNode.Next;
power++;
}
var resultOfLists = firstListSum + secondListSum;
Console.WriteLine($"Sum of the list is {resultOfLists}");
}
}
/// <summary>
/// You have two numbers represented by a linked list, where each node contains a single digit.
/// The digits are stored in reverse order, such that the 1s digit is at the head of the list.
/// Write a function that adds the two numbers and returns the sum as a linked list.
/// </summary>
public static void MainMethod()
{
var sl1 = new SumList();
sl1.AddNodeAtLast(7);
sl1.AddNodeAtLast(1);
sl1.AddNodeAtLast(6);
var sl2 = new SumList();
sl2.AddNodeAtLast(5);
sl2.AddNodeAtLast(9);
sl2.AddNodeAtLast(2);
AddItemsInList(sl1, sl2);
//TO-DO - return the result as a linked list - this is pending!!!
}
