C# (CSharp) RoutingVisualization Model.GetLinksの例

GetLinks() public method

public GetLinks ( ) : string>>.IEnumerable
return	string>>.IEnumerable

コード例 #1

ファイル: DgmlRouteDocFactory.cs プロジェクト: ParticularLabs/RoutingVisualization

 public static XDocument CreateDgml(Model model)
 {
     return new XDocument(
         new XElement(DgmlNamespace + "DirectedGraph",
             new XAttribute("GraphDirection", "LeftToRight"),
             new XAttribute("Layout", "Sugiyama"),
             new XElement(DgmlNamespace + "Nodes", Nodes(model.GetNodes())),
             new XElement(DgmlNamespace + "Links", Links(model.GetLinks())),
             new XElement(DgmlNamespace + "Categories", GetCategories()),
             new XElement(DgmlNamespace + "Properties", GetProperties()),
             new XElement(DgmlNamespace + "Styles", GetStyles())
             )
         );
 }

コード例 #2

ファイル: DgmlRouteDocFactory.cs プロジェクト: xiaoxiongnpu/RoutingVisualization

 public static XDocument CreateDgml(Model model)
 {
     return(new XDocument(
                new XElement(DgmlNamespace + "DirectedGraph",
                             new XAttribute("GraphDirection", "LeftToRight"),
                             new XAttribute("Layout", "Sugiyama"),
                             new XElement(DgmlNamespace + "Nodes", Nodes(model.GetNodes())),
                             new XElement(DgmlNamespace + "Links", Links(model.GetLinks())),
                             new XElement(DgmlNamespace + "Categories", GetCategories()),
                             new XElement(DgmlNamespace + "Properties", GetProperties()),
                             new XElement(DgmlNamespace + "Styles", GetStyles())
                             )
                ));
 }