C# (CSharp) Informedica.GenForm.Settings.Tests.Environments TestGenFormEnvironmentFactoryの例

コード例 #1

        public void HaveDatabaseTestWhenSetToTest()
        {
            var genv = TestGenFormEnvironmentFactory.CreateTestGenFormEnvironment();

            genv.Database = "Test";

            Assert.AreEqual("Test", genv.Database);
        }

コード例 #2

 public void OnlyAddANewGenFormEnvironmentWithAName()
 {
     try
     {
         var genv = TestGenFormEnvironmentFactory.CreateTestGenFormEnvironment();
         genv.Database = "Test";
         _genFormEnvironments.Add(genv);
     }
     catch (System.Exception e)
     {
         Assert.Fail(e.ToString());
     }
 }