public Model()
{
empty = new List<Block>();
board = new Block[4, 4];
for (int i = 0; i < 4; i++)
{
for (int j = 0; j < 4; j++)
{
board[i, j] = new Block();
empty.Add(board[i, j]);
}
}
}
//复制构造函数
public Model(Model old)
{
empty = new List<Block>(old.empty);
board = new Block[4, 4];
for (int i = 0; i < 4; i++)
{
for (int j = 0; j < 4; j++)
{
board[i, j] = new Block(old.board[i,j]);
}
}
}
//复制构造函数
public Block(Block old)
{
hasValue = old.hasValue;
number = old.number;
}
public bool moveUp()
{
bool anyAction = false;
//对于每一列
for (int i = 0; i < 4; i++)
{
//对于这一列里面的每一个元素
for (int j = 0; j < 3; j++)
{
if (board[j, i] == 0)
{
for (int k = j; k < 4; k++)
{
if (board[k, i] != 0)
{
Block tmp = board[j, i];
board[j, i] = board[k, i];
board[k, i] = tmp;
anyAction = true;
break;
}
}
}
}
for (int j = 0; j < 3; j++)
{
if (board[j, i].number == board[j +1, i].number && board[j, i] != 0)
{
board[j, i].number = board[j, i].number * 2;
for (int k = j + 1; k < 3; k++)
{
board[k, i] = board[k+1, i];
}
board[3, i] = new Block();
empty.Add(board[3, i]);
}
}
}
return anyAction;
}
public bool moveRight()
{
bool anyAction = false;
//对于每一行
for (int i = 0; i < 4; i++)
{
//对于这一行里面的每一个元素
for (int j = 3; j > 0; j--)
{
if (board[i, j] == 0)
{
for (int k = j; k >= 0; k--)
{
if (board[i, k] != 0)
{
Block tmp = board[i, j];
board[i, j] = board[i, k];
board[i, k] = tmp;
anyAction = true;
break;
}
}
}
}
for (int j = 3; j > 0; j--)
{
if (board[i, j].number == board[i, j - 1].number && board[i, j] != 0)
{
board[i, j].number = board[i, j].number * 2;
for (int k = j - 1; k > 0; k--)
{
board[i, k] = board[i, k - 1];
}
board[i, 0] = new Block();
empty.Add(board[i, 0]);
}
}
}
return anyAction;
}
public bool moveLeft()
{
bool anyAction = false;
//对于每一行
for (int i = 0; i < 4; i++)
{
//对于这一行里面的每一个元素
for (int j = 0; j < 3; j++)
{
//如果这个格子是空
if (board[i,j]==0)
{
//找到它后面的第一个不是空的格子
for (int k = j; k < 4; k++)
{
if (board[i,k]!=0)
{
//交换这两个格子
//因为empty里面存的是具体的格子的引用，所以不会产生问题
Block tmp = board[i, j];
board[i, j] = board[i, k];
board[i, k] = tmp;
anyAction = true;
break;
}
}
}
}
//检查是否可以合并
//对于前面三个格子中的每个元素
for (int j = 0; j < 3; j++)
{
//如果它与它下一个的数字相同
if (board[i,j].number == board[i,j+1].number&&board[i,j]!=0)
{
//这个格子的数字*=2
board[i, j].number = board[i, j].number * 2;
//把后面的格子移上来
for (int k = j+1; k < 3; k++)
{
board[i, k] = board[i, k+1];
}
//上面的操作事实上把一个引用扔掉了，我们再产生一个空的
board[i, 3] = new Block();
empty.Add(board[i, 3]);
}
}
}
return anyAction;
}
public bool moveDown()
{
bool anyAction = false;
//对于每一列
for (int i = 0; i < 4; i++)
{
//对于这一列里面的每一个元素
for (int j = 3; j > 0; j--)
{
if (board[j, i] == 0)
{
for (int k = j; k >= 0; k--)
{
if (board[k, i] != 0)
{
Block tmp = board[j, i];
board[j, i] = board[k, i];
board[k, i] = tmp;
anyAction = true;
break;
}
}
}
}
for (int j = 3; j > 0; j--)
{
if (board[j, i].number == board[j - 1, i].number && board[j, i] != 0)
{
board[j, i].number = board[j, i].number * 2;
for (int k = j - 1; k > 0; k--)
{
board[k, i] = board[k - 1, i];
}
board[0, i] = new Block();
empty.Add(board[0, i]);
}
}
}
return anyAction;
}
