コード例 #1
0
 static void CreateXmlFromXml()
 {
     Console.WriteLine("".PadLeft(100, '*'));
     Console.WriteLine($"\n\nDe Book App Xml to Xml\n\n");
     Console.WriteLine("".PadLeft(100, '*'));
     Bll.Book    book    = new Bll.Book();
     Dal.BookXml bookXml = new Dal.BookXml(book);
     // bookXml.Book = book;
     bookXml.ReadAll();
     Console.WriteLine(bookXml.Message);
     bookXml.ConnectionString = "Data/Book2";
     bookXml.Create();
     Console.WriteLine(bookXml.Message);
 }
コード例 #2
0
ファイル: Program.cs プロジェクト: timjanssens/Programmeren3
 static void CreateXmlFromXml()
 {
     Console.WriteLine("De Book App Xml to Xml");
     Bll.Book    book    = new Bll.Book();
     Dal.BookXml bookXml = new Dal.BookXml(book);
     bookXml.Book = book;
     bookXml.ReadAll();
     Console.WriteLine(bookXml.Message);
     View.BookConsole view = new View.BookConsole(book);
     view.List();
     bookXml.ConnectionString = "Data/Book2";
     bookXml.Create();
     Console.WriteLine(bookXml.Message);
 }
コード例 #3
0
 static void CreateXmlFromXml()
 {
     Console.WriteLine("".PadLeft(100, '*'));
     Console.WriteLine($"\n\nDe Book App Xml to Xml\n\n");
     Console.WriteLine("".PadLeft(100, '*'));
     Bll.Book    book    = new Bll.Book();
     Dal.BookXml bookXml = new Dal.BookXml(book);
     bookXml.Book = book;
     bookXml.ReadAll();
     Console.WriteLine(bookXml.Message);
     //No need to show the list from originalXml
     // View.BookConsole view = new View.BookConsole(book);
     // view.List();
     bookXml.ConnectionString = "Data/Book2";
     bookXml.Create();
     Console.WriteLine(bookXml.Message);
 }