public MaxSubarrayResult FindMaxSubarray(int[] values, int startIndex, int endIndex)
{
// Divide and Conquer algorithm - O(n * log[n])
var result = new MaxSubarrayResult();
if (startIndex == endIndex)
{
result.StartIndex = startIndex;
result.EndIndex = endIndex;
result.Value = values[startIndex];
return(result);
}
int midIndex = (startIndex + endIndex) / 2;
var leftResult = FindMaxSubarray(values, startIndex, midIndex);
var rightResult = FindMaxSubarray(values, midIndex + 1, endIndex);
var midResult = FindMaxThroughMid(values, startIndex, midIndex, endIndex);
if (leftResult.Value >= midResult.Value && leftResult.Value >= rightResult.Value)
{
return(leftResult);
}
if (rightResult.Value >= leftResult.Value && rightResult.Value >= midResult.Value)
{
return(rightResult);
}
return(midResult);
}
public override MaxSubarrayResult FindMaxSubarray(int[] values)
{
// Fast algorithm by Kadane - O(n)
//
// Discussed briefly in Section 4.1-5 of Introduction to Algorithms, the reader
// is encouraged to develop a non-recursive solution. This algorithm is also known
// as Kadane's algorithm.
//
// More information: https://en.wikipedia.org/wiki/Maximum_subarray_problem
//
// My algorithm here is just slightly enhanced to track the start and end index, as
// well as the actual value.
//
// This is a simple form of dynamic programming - results of solving subproblems
// are passed up the solution chain.
var result = new MaxSubarrayResult()
{
StartIndex = -1,
EndIndex = -1,
Value = Int32.MinValue
};
if (values.Length == 0)
{
return(result);
}
result.StartIndex = 0;
result.EndIndex = 0;
result.Value = values[0];
int currStartIndex = 0;
int currEndIndex = 0;
int currMax = values[0];
for (int endIndex = 1; endIndex < values.Length; endIndex++)
{
if (currMax + values[endIndex] > values[endIndex])
{
currMax += values[endIndex];
currEndIndex = endIndex;
}
else
{
currStartIndex = endIndex;
currEndIndex = endIndex;
currMax = values[endIndex];
}
if (currMax > result.Value)
{
result.StartIndex = currStartIndex;
result.EndIndex = currEndIndex;
result.Value = currMax;
}
}
return(result);
}
public override MaxSubarrayResult FindMaxSubarray(int[] values)
{
// A slow, O(n^2) algorithm
var result = new MaxSubarrayResult()
{
Value = Int32.MinValue
};
for (int startIndex = 0; startIndex < values.Length; startIndex++)
{
int sum = 0;
for (int endIndex = startIndex; endIndex < values.Length; endIndex++)
{
sum += values[endIndex];
if (sum > result.Value)
{
result.StartIndex = startIndex;
result.EndIndex = endIndex;
result.Value = sum;
}
}
}
return(result);
}
static void PrintResult(string method, MaxSubarrayResult result)
{
string heading = "Max Subarray Result, Method = ";
Console.WriteLine("{0}{1}", heading, method);
Console.WriteLine(new String('-', heading.Length + method.Length));
Console.WriteLine("Start Index: {0}", result.StartIndex);
Console.WriteLine("End Index : {0}", result.EndIndex);
Console.WriteLine("Value : {0}", result.Value);
Console.WriteLine();
}
public MaxSubarrayResult FindMaxThroughMid(int[] values, int startIndex, int midIndex, int endIndex)
{
var result = new MaxSubarrayResult()
{
StartIndex = -1,
EndIndex = -1,
Value = Int32.MinValue
};
int maxLeft = Int32.MinValue;
int leftSum = 0;
for (int index = midIndex; index >= startIndex; index--)
{
leftSum += values[index];
if (leftSum > maxLeft)
{
result.StartIndex = index;
maxLeft = leftSum;
}
}
int maxRight = Int32.MinValue;
int rightSum = 0;
for (int index = midIndex + 1; index <= endIndex; index++)
{
rightSum += values[index];
if (rightSum > maxRight)
{
result.EndIndex = index;
maxRight = rightSum;
}
}
result.Value = maxLeft + maxRight;
return(result);
}