C# (CSharp) [email protected]の例

コード例 #1

ファイル: ClientOpenERP.cs プロジェクト: FilRip/IMDEV.Commun

        private [email protected] fieldsViewGetData(string resourceName, int viewId, string viewType, [email protected] context)
        {
            Interfaces.IObject conn;
            object             retour;

            [email protected] ret = null;
            try
            {
                conn     = XmlRpcProxyGen.Create <Interfaces.IObject>();
                conn.Url = url(SERVICE_XMLRPC.@object);
                retour   = conn.executeThreeParam(_config.database, _config.userId, _config.password, resourceName, "fields_view_get", viewId, viewType, context.toArray());
                ret      = new [email protected]();
                ret.copyData((XmlRpcStruct)retour);
            }
            catch (Exception ex)
            {
                if ((_config.reportXmlRpcError) && (ex.GetType() == typeof(XmlRpcFaultException)))
                {
                    throw new Systeme.exceptionOpenERP(Systeme.exceptionOpenERP.ERRORS.LIB_XMLRPC, ex.Message);
                }
            }
            finally
            {
                conn = null;
            }
            return(ret);
        }

コード例 #2

ファイル: ClientOpenERP.cs プロジェクト: FilRip/IMDEV.Commun

        private [email protected] defaultGetData(string resourceName, List <string> listeChamps)
        {
            Interfaces.IObject conn;
            object             retour;

            [email protected] ret = new [email protected]();
            try
            {
                conn     = XmlRpcProxyGen.Create <Interfaces.IObject>();
                conn.Url = url(SERVICE_XMLRPC.@object);
                retour   = conn.execute(_config.database, _config.userId, _config.password, resourceName, "default_get", listeChamps.ToArray());
                ret.copyData((XmlRpcStruct)retour);
                return(ret);
            }
            catch (Exception ex)
            {
                if ((_config.reportXmlRpcError) && (ex.GetType() == typeof(XmlRpcFaultException)))
                {
                    throw new Systeme.exceptionOpenERP(Systeme.exceptionOpenERP.ERRORS.LIB_XMLRPC, ex.Message);
                }
            }
            finally
            {
                conn = null;
            }
            return(null);
        }