コード例 #1
0
        /// <summary>
        /// Searches for a <c>Customer</c> by name.
        /// <remarks>
        /// This method runs in multiple different modes depending on the input:
        ///
        /// If a single term is provided, then it will be searched in both the first and last
        /// names of customers.
        ///
        /// If two terms are provided and delimited with a space, the search will ensure that
        /// the customer's full name includes both search terms.
        ///
        /// If two terms are provided and delimited with a comma, the first term will be
        /// searched only in the last names of customers, and the second term will be
        /// searched only in the first names of customers.
        /// </remarks>
        /// </summary>
        /// <param name="ctx">Store context object.</param>
        /// <param name="name">Search for customers that have this search
        /// string in either their first or last name.</param>
        /// <returns>An <c>IQueryable</c> representing customers that have
        /// either a first or last name containing the search string.</returns>
        public static IQueryable <Customer> FindCustomerByName(this StoreContext ctx, string name)
        {
            name = name.ToLower();

            // Search by either first name or last name when a space is present between two
            // search terms. Both search terms must be present in either the first or last
            // name (or both) of the customer in order to be considered a match.
            var nameComponents = name.Split(' ', 2);

            if (nameComponents.Length == 2)
            {
                var query1 = ctx.FindCustomerByName(nameComponents[0].Trim());
                var query2 = ctx.FindCustomerByName(nameComponents[1].Trim());
                return(query1.Intersect(query2));
            }

            // Search for names in a "lastName,firstName" fashion when a comma is present
            // in the search query.
            var lastThenFirst = name.Split(',', 2);

            if (lastThenFirst.Length == 2)
            {
                var query1 = ctx.FindCustomerByLastName(lastThenFirst[0].Trim());
                var query2 = ctx.FindCustomerByFirstName(lastThenFirst[1].Trim());
                return(query1.Intersect(query2));
            }

            // Standard single term search checks both first and last names.
            return(from customer in ctx.Customers
                   where customer.FirstName.ToLower().Contains(name) ||
                   customer.LastName.ToLower().Contains(name)
                   select customer);
        }
コード例 #2
0
        public void SearchesForCustomerByLastName()
        {
            var options = TestUtil.GetMemDbOptions("SearchesForCustomerByLastName");

            using (var db = new StoreContext(options))
            {
                var customer1 = new Customer("" + Guid.NewGuid().ToString());
                customer1.LastName = "z--bfS/qc" + Guid.NewGuid().ToString();
                db.Add(customer1);

                var customer2 = new Customer("" + Guid.NewGuid().ToString());
                customer2.LastName = "1XfcnY" + Guid.NewGuid().ToString();
                db.Add(customer2);

                var customer3 = new Customer("" + Guid.NewGuid().ToString());
                customer3.LastName = "z--zB8tkm" + Guid.NewGuid().ToString();
                db.Add(customer3);
                db.SaveChanges();

                var findCustomer1 = db.FindCustomerByLastName("bfs");
                Assert.Equal(1, findCustomer1.Count());
                Assert.Equal(customer1.LastName, findCustomer1.First().LastName);

                var findCustomer2 = db.FindCustomerByLastName("cn");
                Assert.Equal(1, findCustomer2.Count());
                Assert.Equal(customer2.LastName, findCustomer2.First().LastName);

                var findCustomers = db.FindCustomerByLastName("z--");
                Assert.Equal(2, findCustomers.Count());
                Assert.Equal(customer1.LastName, findCustomers
                             .Where(c => c.LastName == customer1.LastName)
                             .First()
                             .LastName);
                Assert.Equal(customer3.LastName, findCustomers
                             .Where(c => c.LastName == customer3.LastName)
                             .First()
                             .LastName);
            }
        }