public void Dispose()
{
SourceStates oldValue = (SourceStates)Interlocked.Exchange(ref this.sourceState, (int)SourceStates.Disposed);
if (oldValue != SourceStates.Disposed)
{
if (this.ctRegistration != default(CancellationTokenRegistration))
{
this.ctRegistration.Dispose();
this.ctRegistration = default(CancellationTokenRegistration);
}
if (oldValue == SourceStates.Disposed) // TODO: Check if this is necessary!
{
Task.Run(() => this.Source.TrySetException(new ObjectDisposedException("Lock awaiter was unexpectedly disposed.")));
}
}
}
public bool TrySignalSource(SourceStates state)
{
if ((SourceStates)this.sourceState == SourceStates.Disposed)
{
throw new ObjectDisposedException("SyncTask");
}
int oldValue = -1;
try { } finally
{
if ((oldValue = Interlocked.CompareExchange(ref this.sourceState, (int)state, 0)) == 0)
{
switch (state)
{
case SourceStates.True:
Task.Factory.StartNew(() => { this.Source.TrySetResult(true); });
break;
case SourceStates.False:
Task.Factory.StartNew(() => { this.Source.TrySetResult(false); });
break;
case SourceStates.Canceled:
Task.Factory.StartNew(() => { this.Source.TrySetCanceled(); });
if (this.ctRegistration != default(CancellationTokenRegistration))
{
this.ctRegistration.Dispose();
this.ctRegistration = default(CancellationTokenRegistration);
}
break;
case SourceStates.Disposed:
throw new ArgumentException("SyncTask cannot be disposed this way.");
default:
break;
}
}
}
return(oldValue == 0);
}
/// <summary>
/// OnNext takes a tuple of an observation and a sequence of
/// states that might have emitted this observation (the
/// FROM states). The name of the tuple is "value". The
/// observation is in "value.Item1" and the sequence of
/// states is in "value.Item2".
/// </summary>
public void OnNext(Tuple <O, IEnumerable <S> > value)
{
Contract.Requires(value.Item2 != null);
// Contract.Requires fails here due to visibility of the properties.
Contract.Assert(Iff(TargetStates == null, LastV == null));
// True only first time around -- at bootstrapping time.
if (TargetStates == null)
{
// Initialize the HISTORY LIST of maps from state to
// probability-of-most-probable-path.
_V = new List <Dictionary <S, double> >();
// Initialize the map from state to
// most-probable-path-leading-to-state.
Path = new Dictionary <S, List <S> >();
// Initialize the FIRST map from state to probability
// of most-probable-path leading to the state.
var firstV = new Dictionary <S, double>();
// value.Item2 contains the FROM states: the states
// that might have emitted this observation. Now
// compute the probabilities for transition to all the
// TO states. In this bootstrapping case, the
// probabilities are simply the emission
// probabilities -- the probabilities that the state
// produced this observation -- times the probability
// that the system was in that state.
foreach (var state in value.Item2)
{
// The probability of the most probable path
// leading to "state" given observation is the
// a-priori probability of state times the
// conditional probability of observation given
// the state. Observation is in the slot
// "value.Item1."
firstV[state] =
StartingProbabilities(state) *
EmissionProbabilities(state, value.Item1);
// The state that yielded the transition to this
// most probable path is just "state" itself.
Path[state] = new List <S>();
Path[state].Add(state);
}
// The possible targets for the next transition are in
// the states, in-turn in slot "value.Item2."
TargetStates = value.Item2;
_V.Add(firstV);
LastV = firstV;
return;
}
// The source states for this observation are the target
// states from the last observation (Viterbi, strictly
// speaking, has a memory of ONE transition). In case of
// the first observation -- the bootstrapping case, this
// is also true, it just so happens that the source and
// target states are the same during bootstrapping.
SourceStates = TargetStates;
// The target states for this observation are in the input
// to OnNext.
TargetStates = value.Item2;
// Space for the new probabilities of the
// most-probable-paths leading to each state.
var nextV = new Dictionary <S, double>();
// and for each candidate target state . . .
foreach (var target in TargetStates)
{
// . . . find the SOURCE state that leads to the most
// probable path to the target.
//
// Maximize over the prior states: the transition
// probabilities from the source state, times the
// conditional probabilities of seeing the actual
// observation given the candidate source state, times
// the probability of the most-probable-path leading
// to the source state. Use the LINQ non-standard
// query operator "ArgAndMax," which, for any
// IEnumerable, finds the input (the arg or "source")
// that produces the maximum value of its given
// function (lambda expression), and also that maximum
// value, returning both the argument and the maximum
// in an instance of class ArgumentValuePair.
//
// In this lambda expression, "target" is fixed
// (closed over).
var maxStateAndProb = SourceStates.ArgAndMax(source =>
{
// probability of the most probable path that led
// to source
var a = LastV[source];
// transition probability from source to target
var b = TransitionProbabilities(source, target);
// probability of seeing actual observation if we
// are in the target state; observation is stored
// in value.Item1.
var c = EmissionProbabilities(target, value.Item1);
return(a * b * c);
});
// After this point, we have found the SOURCE state
// that produces the most probable path to the given
// target state and yielding the given observation.
// Save the probability of that most-probable-path.
nextV[target] = maxStateAndProb.Value;
// Copy the most probable path that led to the source
// state that yields the maximum probability. I must
// copy it because this path might be the same for
// multiple targets, and each target will need its own
// copy of the prior path to append itself to.
var newpath = new List <S>(Path[maxStateAndProb.Argument]);
// Append the current state.
newpath.Add(target);
// Replace the path to the current target with the
// refreshed one.
Path[target] = newpath;
}
_V.Add(nextV);
LastV = nextV;
}