private void selaaReseptejäToolStripMenuItem_Click(object sender, EventArgs e)
{
FileStream stream;
OpenFileDialog o;
OpenFileStream(out stream, out o);
XmlSerializer serializer = new XmlSerializer(typeof(ReseptiModel));
if (o.ShowDialog() == DialogResult.OK)
{
try{
if ((stream = (FileStream)o.OpenFile()) != null)
{
using (stream){
ReseptiModel = (ReseptiModel)serializer.Deserialize(stream);
ApplyVariables();
}
}
}
catch (Exception eih) {
throw new Exception(eih.Message);
}
}
}
public NewRecipe()
{
InitializeComponent();
m = new ReseptiModel();
}