コード例 #1
0
        protected ActionResult ErrorResult(HttpStatusCode statusCode, string message = null, Exception exception = null)
        {
            var code           = statusCode.ChangeType <string>();
            var isDebug        = HttpContext.IsDebuggingEnabled;
            var errorViewModel = new ErrorViewModel(statusCode, errorMessage: message);

            Response.StatusCode = errorViewModel.Code;

            if (!Request.IsAjaxRequest())
            {
                return(View(nameof(ErrorsController.Index), errorViewModel));
            }

            ModelState.AddModelError(code, errorViewModel.Message);

            return(JsonError(ModelState));
        }