//Added by Manjot on 08/Aug/2017
public ActionResult GetXMLPath(string FileName, int RecordID)
{
Ctx ct = Session["ctx"] as Ctx;
DBXml _obj = new DBXml();
return(Json(JsonConvert.SerializeObject(_obj.CreateJDBCDataSourceXml(ct, FileName, RecordID)), JsonRequestBehavior.AllowGet));
}