/// <summary>
 /// 初始化四叉树递归模拟
 /// </summary>
 /// <param name="f">递归作用函数</param>
 /// <param name="f1">递归条件函数1</param>
 /// <param name="f2">递归条件函数2</param>
 /// <param name="f3">递归条件函数3</param>
 /// <param name="f4">递归条件函数4</param>
 /// <param name="stackElem">递归作用对象</param>
 public QuadtreeRecurrenceHelper(Func <StackElem <StackElemData>, StackElem <StackElemData> > f,
                                 Func <StackElem <StackElemData>, bool> f1, Func <StackElem <StackElemData>, bool> f2, Func <StackElem <StackElemData>, bool> f3, Func <StackElem <StackElemData>, bool> f4,
                                 StackElem <StackElemData> stackElem)
 {
     this.f1        = f1;
     this.f2        = f2;
     this.f3        = f3;
     this.f4        = f4;
     this.f         = f;
     this.stackElem = stackElem;
 }
        public StackElem <StackElemData> Recurrence()
        {
            int CaseNum = 0;


            do
            {
                if (stackElem.fragmentIndex == 5)//如果将要执行第5个片段,则表示一次递归完了
                {
                    CaseNum = 5;
                }

                if (CaseNum == 0)      //代表进入了函数
                {
                    f(stackElem);      //实施操作
                    if (f1(stackElem)) //当满足f1234函数时判断为true后,代表需要进行递归,其参数stackElem里面的OtherParameter就会更新为下次需要的参数
                    {
                        CaseNum = 1;   //记录此次位置,便于后面更改为下次递归的完成后的开始位置
                    }
                    else if (f2(stackElem))
                    {
                        CaseNum = 2;
                    }
                    else if (f3(stackElem))
                    {
                        CaseNum = 3;
                    }
                    else if (f4(stackElem))
                    {
                        CaseNum = 4;
                    }
                }
                else if (CaseNum != 5)
                {//pop后,接着记录的caseNum执行
                    while (true)
                    {
                        if (CaseNum == 1)
                        {
                            if (f1(stackElem))
                            {
                                CaseNum = 1; break;
                            }
                            if (f2(stackElem))
                            {
                                CaseNum = 2; break;
                            }
                            if (f3(stackElem))
                            {
                                CaseNum = 3; break;
                            }
                            if (f4(stackElem))
                            {
                                CaseNum = 4; break;
                            }
                        }
                        else if (CaseNum == 2)
                        {
                            if (f2(stackElem))
                            {
                                CaseNum = 2; break;
                            }
                            if (f3(stackElem))
                            {
                                CaseNum = 3; break;
                            }
                            if (f4(stackElem))
                            {
                                CaseNum = 4; break;
                            }
                        }
                        else if (CaseNum == 3)
                        {
                            if (f3(stackElem))
                            {
                                CaseNum = 3; break;
                            }
                            if (f4(stackElem))
                            {
                                CaseNum = 4; break;
                            }
                        }
                        else if (CaseNum == 4)
                        {
                            if (f4(stackElem))
                            {
                                CaseNum = 4; break;
                            }
                        }
                        CaseNum = 0; break;
                    }
                }

                if (CaseNum == 0 || CaseNum == 5)
                { //条件未匹配到或者已经递归完成,pop出函数
                    if (RecurrenceStack.Count == 0)
                    {
                        break;
                    }
                    StackElem <StackElemData> elem = RecurrenceStack.Pop();
                    CaseNum   = elem.fragmentIndex;//此处不对
                    stackElem = elem;
                    continue;
                }
                //    else RecurrenceStack.Push(new StackElem<DataType> { fragmentIndex = CaseNum, OtherParameter = stackElem.OtherParameter });
                else
                {
                    switch (CaseNum)
                    {
                    case 1:    //记录出函数时的片段位置,然后进入函数(push)
                        CaseNum++;
                        RecurrenceStack.Push(new StackElem <StackElemData> {
                            fragmentIndex = CaseNum, OtherParameter = new StackElemData {
                                fx = stackElem.OtherParameter.fx, index = stackElem.OtherParameter.index
                            }
                        });
                        break;

                    case 2:
                        CaseNum++;
                        RecurrenceStack.Push(new StackElem <StackElemData> {
                            fragmentIndex = CaseNum, OtherParameter = new StackElemData {
                                fx = stackElem.OtherParameter.fx, index = stackElem.OtherParameter.index
                            }
                        });
                        break;

                    case 3:
                        CaseNum++;
                        RecurrenceStack.Push(new StackElem <StackElemData> {
                            fragmentIndex = CaseNum, OtherParameter = new StackElemData {
                                fx = stackElem.OtherParameter.fx, index = stackElem.OtherParameter.index
                            }
                        });
                        break;

                    case 4:
                        CaseNum++;
                        RecurrenceStack.Push(new StackElem <StackElemData> {
                            fragmentIndex = CaseNum, OtherParameter = new StackElemData {
                                fx = stackElem.OtherParameter.fx, index = stackElem.OtherParameter.index
                            }
                        });
                        break;
                    }
                    CaseNum = 0;//进入函数信号
                }
            } while (RecurrenceStack.Count != 0);
            return(stackElem);
        }