Esempio n. 1
0
 public int len;        //长度
 public BFSNode(int x, int y)
 {
     this.x      = x;
     this.y      = y;
     this.parent = null;
     len         = 1;
 }
Esempio n. 2
0
        //static void Main()
        //{
        //    //迷宫
        //    int[,] maze = {
        //       { 0, 1, 0, 0, 0 },
        //       { 0, 1, 0, 1, 0 },
        //       { 0, 0, 0, 0, 0 },
        //       { 0, 1, 1, 1, 0 },
        //       { 0, 0, 0, 1, 0 },
        //    };
        //    BFS b = new BFS();
        //    BFSNode r = b.bfs(new BFSNode(0, 0), new BFSNode(4, 4),maze);
        //    //if(r==null)
        //    Console.WriteLine(r.x+" "+r.y+" "+r.len);

        //   while(r!=null)
        //    {
        //        Console.WriteLine(r.x + "__"+r.y);
        //        r = r.parent;
        //    }

        //}
        public BFSNode bfs(BFSNode start, BFSNode end, int [,] maze)
        {
            Queue <BFSNode> q = new Queue <BFSNode>();

            int[,] visit = new int[maze.GetLength(0), maze.GetLength(1)]; //是否访问过
            q.Enqueue(start);                                             //加入起点
            visit[start.x, start.y] = 1;                                  //设置访问过
            Console.WriteLine(start.x + " " + start.y);
            while (q.Count > 0)
            {
                BFSNode now = q.Dequeue();                                                                                                   //当前节点
                for (int i = 0; i < 4; i++)                                                                                                  //当前节点的四个方位
                {
                    BFSNode next = new BFSNode(now.x + dir[i, 0], now.y + dir[i, 1]);                                                        //下一个方向节点

                    if (next.x >= 0 && next.x < maze.GetLength(0) && next.y >= 0 && next.y < maze.GetLength(1) && maze[next.x, next.y] != 1) //该值是否存在
                    {
                        next.parent = now;
                        next.len    = now.len + 1;//路径加一
                        if (next.x == end.x && next.y == end.y)
                        {
                            return(next);//返回终点
                        }
                        if (visit[next.x, next.y] == 0)
                        {
                            visit[next.x, next.y] = 1; //设置为访问
                            q.Enqueue(next);           //加入队列
                        }
                    }
                }
                Console.WriteLine();
            }
            return(null);
        }