Esempio n. 1
0
        public static long Problem45()
        {
            /*
             * Triangle, pentagonal, and hexagonal numbers are generated by the following formulae:
             *
             * Triangle	    Tn=n(n+1)/2	    1, 3, 6, 10, 15, ...
             * Pentagonal	    Pn=n(3n−1)/2	    1, 5, 12, 22, 35, ...
             * Hexagonal	    Hn=n(2n−1)	    1, 6, 15, 28, 45, ...
             * It can be verified that T285 = P165 = H143 = 40755.
             *
             * Find the next triangle number that is also pentagonal and hexagonal.
             */

            long n = 286L;
            long l = 0L;

            do
            {
                l = (n * (n + 1)) / 2;
                n = n + 1;
            } while (!Formulas.isTriangular(l) || !Formulas.isPentagonal(l) || !Formulas.isHexagonal(l));



            return(l);
        }
Esempio n. 2
0
        public static long Problem42()
        {
            long result = 0;

            string text = System.IO.File.ReadAllText(@"res\p042_words.txt");

            foreach (string word in text.Split(','))
            {
                string w = word.Replace("\"", "");

                long val = 0;

                foreach (char c in w)
                {
                    val += c - 64;
                }

                if (Formulas.isTriangular(val))
                {
                    result++;
                }
            }

            return(result);
        }