/// <summary>
/// Parses a chain from a sentence or phrase.
/// Does not attempt to learn links from it (only learns tokens in isolation);
/// learning links is done by calling <see cref="LearnToWrite(Chain)"/>.
/// Parsing a chain without using spaces or by guessing at capitalization rules isn't really possible...
/// Well maybe DromedaryCaseEnterpriseyJavaBeanAppletFactoryFactoryStuffImpl, but that will have to wait...
/// </summary>
/// <returns></returns>
public Chain ParseSentence(string sentence, CultureInfo c = null)
{
// split on whitespace
// note that we're leaving punctuation as part of the words
// in addition to being lazy, it also makes for more realistic sentences when generating chains :D
var words = sentence.Split(' ', '\r', '\n', '\t');
// make a chain!
var chain = new Chain(Capitalization.FirstToken, true, c);
// start!
chain.Append(BeginEndToken);
// add ye tokens
foreach (var word in words)
{
LearnToken(word);
chain.Append(Lexicon[word]);
}
// end!
chain.Append(BeginEndToken);
// ITS OVAR
return(chain);
}
/// <summary>
/// Builds a randomized chain using weighted values.
/// </summary>
/// <param name="cap"></param>
/// <param name="spaces"></param>
/// <param name="c"></param>
/// <param name="preferStopAfter">How long until we ask to stop ASAP?</param>
/// <param name="demandStopAfter">How long until we call an immediate halt to generation?</param>
/// <returns></returns>
public Chain WriteChain(Capitalization cap, bool spaces, int preferStopAfter, int demandStopAfter, CultureInfo c = null)
{
var chain = new Chain(cap, spaces, c);
var cur = BeginEndToken;
bool runon = false; // did we get cut off?
do
{
if (!cur.Links.Any())
{
throw new InvalidOperationException($"Token \"{cur}\" has no outgoing links.");
}
cur = cur.Links.PickWeighted(Rng);
if (chain.Tokens.Count() >= demandStopAfter)
{
cur = BeginEndToken;
runon = true;
}
if (chain.Tokens.Count() >= preferStopAfter && cur.Links.ContainsKey(BeginEndToken))
{
cur = BeginEndToken;
runon = true;
}
chain.Append(cur);
} while (cur != BeginEndToken);
chain.IsRunon = runon;
return(chain);
}