Esempio n. 1
0
        /**
         * Calculates a.modInverse(p) Based on: Savas, E; Koc, C "The Montgomery Modular
         * Inverse - Revised"
         */

        public static BigInteger ModInverseMontgomery(BigInteger a, BigInteger p)
        {
            if (a.Sign == 0)
            {
                // ZERO hasn't inverse
                // math.19: BigInteger not invertible
                throw new ArithmeticException(Messages.math19);
            }

            if (!BigInteger.TestBit(p, 0))
            {
                // montgomery inverse require even modulo
                return(ModInverseLorencz(a, p));
            }

            int m = p.numberLength * 32;
            // PRE: a \in [1, p - 1]
            BigInteger u, v, r, s;

            u = p.Copy();             // make copy to use inplace method
            v = a.Copy();
            int max = System.Math.Max(v.numberLength, u.numberLength);

            r           = new BigInteger(1, 1, new int[max + 1]);
            s           = new BigInteger(1, 1, new int[max + 1]);
            s.Digits[0] = 1;
            // s == 1 && v == 0

            int k = 0;

            int lsbu = u.LowestSetBit;
            int lsbv = v.LowestSetBit;
            int toShift;

            if (lsbu > lsbv)
            {
                BitLevel.InplaceShiftRight(u, lsbu);
                BitLevel.InplaceShiftRight(v, lsbv);
                BitLevel.InplaceShiftLeft(r, lsbv);
                k += lsbu - lsbv;
            }
            else
            {
                BitLevel.InplaceShiftRight(u, lsbu);
                BitLevel.InplaceShiftRight(v, lsbv);
                BitLevel.InplaceShiftLeft(s, lsbu);
                k += lsbv - lsbu;
            }

            r.Sign = 1;
            while (v.Sign > 0)
            {
                // INV v >= 0, u >= 0, v odd, u odd (except last iteration when v is even (0))

                while (u.CompareTo(v) > BigInteger.EQUALS)
                {
                    Elementary.inplaceSubtract(u, v);
                    toShift = u.LowestSetBit;
                    BitLevel.InplaceShiftRight(u, toShift);
                    Elementary.inplaceAdd(r, s);
                    BitLevel.InplaceShiftLeft(s, toShift);
                    k += toShift;
                }

                while (u.CompareTo(v) <= BigInteger.EQUALS)
                {
                    Elementary.inplaceSubtract(v, u);
                    if (v.Sign == 0)
                    {
                        break;
                    }
                    toShift = v.LowestSetBit;
                    BitLevel.InplaceShiftRight(v, toShift);
                    Elementary.inplaceAdd(s, r);
                    BitLevel.InplaceShiftLeft(r, toShift);
                    k += toShift;
                }
            }
            if (!u.IsOne)
            {
                // in u is stored the gcd
                // math.19: BigInteger not invertible.
                throw new ArithmeticException(Messages.math19);
            }
            if (r.CompareTo(p) >= BigInteger.EQUALS)
            {
                Elementary.inplaceSubtract(r, p);
            }

            r = p - r;

            // Have pair: ((BigInteger)r, (Integer)k) where r == a^(-1) * 2^k mod (module)
            int n1 = CalcN(p);

            if (k > m)
            {
                r = MonPro(r, BigInteger.One, p, n1);
                k = k - m;
            }

            r = MonPro(r, BigInteger.GetPowerOfTwo(m - k), p, n1);
            return(r);
        }
Esempio n. 2
0
        /**
         *
         * Based on "New Algorithm for Classical Modular Inverse" Róbert Lórencz.
         * LNCS 2523 (2002)
         *
         * @return a^(-1) mod m
         */

        private static BigInteger ModInverseLorencz(BigInteger a, BigInteger modulo)
        {
            // PRE: a is coprime with modulo, a < modulo

            int max = System.Math.Max(a.numberLength, modulo.numberLength);

            int[] uDigits = new int[max + 1];             // enough place to make all the inplace operation
            int[] vDigits = new int[max + 1];
            Array.Copy(modulo.Digits, 0, uDigits, 0, modulo.numberLength);
            Array.Copy(a.Digits, 0, vDigits, 0, a.numberLength);
            BigInteger u = new BigInteger(modulo.Sign,
                                          modulo.numberLength,
                                          uDigits);
            BigInteger v = new BigInteger(a.Sign, a.numberLength, vDigits);

            BigInteger r = new BigInteger(0, 1, new int[max + 1]);             // BigInteger.ZERO;
            BigInteger s = new BigInteger(1, 1, new int[max + 1]);

            s.Digits[0] = 1;
            // r == 0 && s == 1, but with enough place

            int coefU = 0, coefV = 0;
            int n = modulo.BitLength;
            int k;

            while (!IsPowerOfTwo(u, coefU) && !IsPowerOfTwo(v, coefV))
            {
                // modification of original algorithm: I calculate how many times the algorithm will enter in the same branch of if
                k = HowManyIterations(u, n);

                if (k != 0)
                {
                    BitLevel.InplaceShiftLeft(u, k);
                    if (coefU >= coefV)
                    {
                        BitLevel.InplaceShiftLeft(r, k);
                    }
                    else
                    {
                        BitLevel.InplaceShiftRight(s, System.Math.Min(coefV - coefU, k));
                        if (k - (coefV - coefU) > 0)
                        {
                            BitLevel.InplaceShiftLeft(r, k - coefV + coefU);
                        }
                    }
                    coefU += k;
                }

                k = HowManyIterations(v, n);
                if (k != 0)
                {
                    BitLevel.InplaceShiftLeft(v, k);
                    if (coefV >= coefU)
                    {
                        BitLevel.InplaceShiftLeft(s, k);
                    }
                    else
                    {
                        BitLevel.InplaceShiftRight(r, System.Math.Min(coefU - coefV, k));
                        if (k - (coefU - coefV) > 0)
                        {
                            BitLevel.InplaceShiftLeft(s, k - coefU + coefV);
                        }
                    }
                    coefV += k;
                }

                if (u.Sign == v.Sign)
                {
                    if (coefU <= coefV)
                    {
                        Elementary.completeInPlaceSubtract(u, v);
                        Elementary.completeInPlaceSubtract(r, s);
                    }
                    else
                    {
                        Elementary.completeInPlaceSubtract(v, u);
                        Elementary.completeInPlaceSubtract(s, r);
                    }
                }
                else
                {
                    if (coefU <= coefV)
                    {
                        Elementary.completeInPlaceAdd(u, v);
                        Elementary.completeInPlaceAdd(r, s);
                    }
                    else
                    {
                        Elementary.completeInPlaceAdd(v, u);
                        Elementary.completeInPlaceAdd(s, r);
                    }
                }
                if (v.Sign == 0 || u.Sign == 0)
                {
                    // math.19: BigInteger not invertible
                    throw new ArithmeticException(Messages.math19);
                }
            }

            if (IsPowerOfTwo(v, coefV))
            {
                r = s;
                if (v.Sign != u.Sign)
                {
                    u = -u;
                }
            }
            if (BigInteger.TestBit(u, n))
            {
                if (r.Sign < 0)
                {
                    r = -r;
                }
                else
                {
                    r = modulo - r;
                }
            }
            if (r.Sign < 0)
            {
                r += modulo;
            }

            return(r);
        }
Esempio n. 3
0
        /**
         * @param m a positive modulus
         * Return the greatest common divisor of op1 and op2,
         *
         * @param op1
         *            must be greater than zero
         * @param op2
         *            must be greater than zero
         * @see BigInteger#gcd(BigInteger)
         * @return {@code GCD(op1, op2)}
         */

        public static BigInteger GcdBinary(BigInteger op1, BigInteger op2)
        {
            // PRE: (op1 > 0) and (op2 > 0)

            /*
             * Divide both number the maximal possible times by 2 without rounding
             * gcd(2*a, 2*b) = 2 * gcd(a,b)
             */
            int lsb1      = op1.LowestSetBit;
            int lsb2      = op2.LowestSetBit;
            int pow2Count = System.Math.Min(lsb1, lsb2);

            BitLevel.InplaceShiftRight(op1, lsb1);
            BitLevel.InplaceShiftRight(op2, lsb2);

            BigInteger swap;

            // I want op2 > op1
            if (op1.CompareTo(op2) == BigInteger.GREATER)
            {
                swap = op1;
                op1  = op2;
                op2  = swap;
            }

            do
            {
                // INV: op2 >= op1 && both are odd unless op1 = 0

                // Optimization for small operands
                // (op2.bitLength() < 64) implies by INV (op1.bitLength() < 64)
                if ((op2.numberLength == 1) ||
                    ((op2.numberLength == 2) && (op2.Digits[1] > 0)))
                {
                    op2 = BigInteger.FromInt64(Division.GcdBinary(op1.ToInt64(),
                                                                  op2.ToInt64()));
                    break;
                }

                // Implements one step of the Euclidean algorithm
                // To reduce one operand if it's much smaller than the other one
                if (op2.numberLength > op1.numberLength * 1.2)
                {
                    op2 = BigMath.Remainder(op2, op1);
                    if (op2.Sign != 0)
                    {
                        BitLevel.InplaceShiftRight(op2, op2.LowestSetBit);
                    }
                }
                else
                {
                    // Use Knuth's algorithm of successive subtract and shifting
                    do
                    {
                        Elementary.inplaceSubtract(op2, op1);                         // both are odd
                        BitLevel.InplaceShiftRight(op2, op2.LowestSetBit);            // op2 is even
                    } while (op2.CompareTo(op1) >= BigInteger.EQUALS);
                }
                // now op1 >= op2
                swap = op2;
                op2  = op1;
                op1  = swap;
            } while (op1.Sign != 0);
            return(op2 << pow2Count);
        }