public SimpleBSTNode Ceil(SimpleBSTNode x, int key)
{
if (x == null)
{
return(null);
}
int cmp = key.CompareTo(x.key);
if (cmp == 0)
{
return(x);
}
else if (cmp > 0)
{
return(Ceil(x.right, key));
}
else
{ //reached a node whose key is more than input key
//check if the right subtree of this node.
//if floor in the right subtree is null, then this node's key is the floor
SimpleBSTNode t = Ceil(x.left, key);
if (t != null)
{
return(t);
}
else
{
return(x);
}
}
}
//Hibbard deletion : replace node to be deleted with smallest node in right subtree and make appropriate adjustments
//Problem with Hibbard deletion : it is assymetric. After a series of insertions and deletions with this technique,
//the height of the tree becomes sqrt(N) as opposed to log(N). It might make a difference b/w acceptable and unacceptable
//solution in real world applications. Simple and efficient deletion for BSTs is a long standing open problem. - Robert Sedgewick
private SimpleBSTNode Delete(SimpleBSTNode x, int key)
{
if (x == null)
{
return(null);
}
int cmp = key.CompareTo(x.key);
if (cmp < 0)
{
x.left = Delete(x.left, key);
}
else if (cmp > 0)
{
x.right = Delete(x.right, key);
}
else
{//cmp==0 => x is the node to be deleted
if (x.right == null)
{
return(x.left);
}
SimpleBSTNode t = x;
x = Min(t.right);
x.right = DeleteMin(t.right);
x.left = t.left;
}
x.count = 1 + Size(x.left) + Size(x.right);
return(x);
}
private SimpleBSTNode Put(SimpleBSTNode x, int key, int val)
{
if (x == null)
{
x = new SimpleBSTNode(key, val);
}
else
{
int cmp = key.CompareTo(x.key);
if (cmp < 0)
{
x.left = Put(x.left, key, val);
}
if (cmp > 0)
{
x.right = Put(x.right, key, val);
}
if (cmp == 0)
{
x.val = val;
}
}
x.count = 1 + Size(x.left) + Size(x.right);
return(x);
}
public SimpleBSTNode Min(SimpleBSTNode x)
{
while ((x != null) && (x.left != null))
{
x = x.left;
}
return(x);
}
public int Max(SimpleBSTNode x)
{
while ((x != null) && (x.right != null))
{
x = x.right;
}
return(x.key);
}
public SimpleBSTNode DeleteMin(SimpleBSTNode x)
{
if (x.left == null)
return x.right;
x.left = DeleteMin(x.left);
x.count = 1 + Size(x.left) + Size(x.right);
return x;
}
public int Size(SimpleBSTNode x)
{
if (x == null)
{
return(0);
}
return(x.count);
}
private void Inorder(SimpleBSTNode x, Queue q)
{
if (x == null)
{
return;
}
Inorder(x.left, q);
q.Enqueue(x);
Inorder(x.right, q);
}
public SimpleBSTNode DeleteMin(SimpleBSTNode x)
{
if (x.left == null)
{
return(x.right);
}
x.left = DeleteMin(x.left);
x.count = 1 + Size(x.left) + Size(x.right);
return(x);
}
public int Rank(SimpleBSTNode x, int key)
{
if (x == null)
{
return(0);
}
int cmp = key.CompareTo(x.key);
if (cmp == 0)
{
return(Size(x.left));
}
else if (cmp < 0)
{
return(Rank(x.left, key));
}
else
{
return(1 + Size(x.left) + Rank(x.right, key));
}
}
public int Get(int key)
{
SimpleBSTNode x = root;
while (x != null)
{
int cmp = key.CompareTo(x.key);
if (cmp == 0)
{
return(x.val);
}
if (cmp < 0)
{
x = x.left;
}
if (cmp > 0)
{
x = x.right;
}
}
return(-1); //null
}
public SimpleBSTNode Floor(SimpleBSTNode x, int key)
{
if (x == null)
return null;
int cmp = key.CompareTo(x.key);
if (cmp == 0)
return x;
else if (cmp < 0)
return Floor(x.left, key);
else
{ //reached a node whose key is less than input key
//check if the right subtree of this node.
//if floor in the right subtree is null, then this node's key is the floor
SimpleBSTNode t = Floor(x.right, key);
if (t != null)
return t;
else
return x;
}
}
private void RangeSelect(SimpleBSTNode x, int lo, int hi, Queue q)
{
if (x == null)
{
return;
}
if (x.key.CompareTo(lo) < 0) //lower bound of interval more than current node
{
RangeSelect(x.right, lo, hi, q);
}
else if (x.key.CompareTo(hi) > 0) //upper bound of interval less than current node
{
RangeSelect(x.left, lo, hi, q);
}
else
{
//Inorder(x, q);
RangeSelect(x.left, lo, hi, q);
q.Enqueue(x);
RangeSelect(x.right, lo, hi, q);
}
}
public int Max(SimpleBSTNode x)
{
while ((x != null) && (x.right != null))
x = x.right;
return x.key;
}
public void Put(int key, int val)
{
root = Put(root, key, val);
}
public void Put(int key, int val)
{
root = Put(root, key, val);
}
public int count; //count of nodes in subtree rooted at current node
public SimpleBSTNode(int key, int val)
{
this.key = key; this.val = val;
//left = null; right = null;
left = right = null;
}
public int Rank(SimpleBSTNode x, int key)
{
if (x == null)
return 0;
int cmp = key.CompareTo(x.key);
if (cmp == 0)
return Size(x.left);
else if (cmp < 0)
return Rank(x.left, key);
else
{
return 1 + Size(x.left) + Rank(x.right, key);
}
}
public int Size(SimpleBSTNode x)
{
if (x == null)
return 0;
return x.count;
}
//Hibbard deletion : replace node to be deleted with smallest node in right subtree and make appropriate adjustments
//Problem with Hibbard deletion : it is assymetric. After a series of insertions and deletions with this technique,
//the height of the tree becomes sqrt(N) as opposed to log(N). It might make a difference b/w acceptable and unacceptable
//solution in real world applications. Simple and efficient deletion for BSTs is a long standing open problem. - Robert Sedgewick
private SimpleBSTNode Delete(SimpleBSTNode x, int key)
{
if (x == null)
return null;
int cmp = key.CompareTo(x.key);
if (cmp < 0)
x.left = Delete(x.left, key);
else if (cmp > 0)
x.right = Delete(x.right, key);
else
{//cmp==0 => x is the node to be deleted
if (x.right == null)
return x.left;
SimpleBSTNode t = x;
x = Min(t.right);
x.right = DeleteMin(t.right);
x.left = t.left;
}
x.count = 1 + Size(x.left) + Size(x.right);
return x;
}
private void Inorder(SimpleBSTNode x,Queue q)
{
if (x == null)
return;
Inorder(x.left, q);
q.Enqueue(x);
Inorder(x.right, q);
}
public void Delete(int key)
{
root = Delete(root, key);
}
private SimpleBSTNode Put(SimpleBSTNode x, int key, int val)
{
if (x == null)
{
x = new SimpleBSTNode(key, val);
}
else
{
int cmp = key.CompareTo(x.key);
if (cmp < 0)
x.left = Put(x.left, key, val);
if (cmp > 0)
x.right = Put(x.right, key, val);
if (cmp == 0)
x.val = val;
}
x.count = 1 + Size(x.left) + Size(x.right);
return x;
}
private void RangeSelect(SimpleBSTNode x, int lo, int hi, Queue q)
{
if (x == null)
return;
if (x.key.CompareTo(lo) < 0) //lower bound of interval more than current node
RangeSelect(x.right, lo, hi,q);
else if (x.key.CompareTo(hi) > 0) //upper bound of interval less than current node
RangeSelect(x.left, lo, hi,q);
else
{
//Inorder(x, q);
RangeSelect(x.left, lo, hi, q);
q.Enqueue(x);
RangeSelect(x.right, lo, hi, q);
}
}
public SimpleBSTNode(int key, int val)
{
this.key = key; this.val = val;
//left = null; right = null;
left = right = null;
}
public SimpleBSTNode Min(SimpleBSTNode x)
{
while ((x != null)&&(x.left!=null))
x = x.left;
return x;
}
public void Delete(int key)
{
root = Delete(root, key);
}