Esempio n. 1
0
        public GridBoard Clone()
        {
            GridBoard result = new GridBoard(this.Size);

            for (int i = 0; i < Data.Length; i++)
            {
                for (int j = 0; j < Data.Length; j++)
                {
                    result[i, j] = this[i, j];
                }
            }
            return(result);
        }
Esempio n. 2
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        public static void Main(string[] args)
        {
            var       Board = new GridBoard(Size: 14);//建立棋盤
            Stopwatch watch = new Stopwatch();

            watch.Start();
            var result = KnightTour(Board);

            watch.Stop();
            Console.WriteLine($"運算耗時:{watch.Elapsed}");
            Console.WriteLine(result.ToString());
            Console.ReadKey();
        }
Esempio n. 3
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        public static GridBoard KnightTour(GridBoard Board, Point Start, int Step = 0)
        {
            Board[Start] = ++Step;//將目前座標填入值

            if (Step == Board.Size * Board.Size)
            {
                return(Board);                                         //已經完成巡邏
            }
            foreach (var NextPoint in Steps                            //列舉可移動座標並且帶入任務檢驗
                     .Select(x => x.Move(Start))                       //將移動後的座標列出
                     .Where(x => Board.InBoard(x) && Board.CanMove(x)) //篩選出可以使用的座標(剔除超出邊界與已經使用過的)
                     .Select(x => {
                var NextBoard = Board.Clone();                         //複製目前棋盤狀態
                NextBoard[x] = Step + 1;                               //在移動後的位置填寫新的step值

                var NextNextMove = (from t in Steps select t.Move(x)).Where(y => NextBoard.InBoard(y) && NextBoard.CanMove(y));
                //計算下一節點可移動的路徑集合

                return(new {                      //建立匿名物件
                    Point = x,                    //下一階層移動座標
                    Degree = NextNextMove.Count() //計算下一節點可移動的路徑數量
                });
            })
                     .OrderBy(x => x.Degree)//使用可移動數量進行遞增排序
                     )
            {
                var NextLevelResult = KnightTour(Board, NextPoint.Point, Step);//使用遞迴並指派下個移動位置
                if (NextLevelResult != null)
                {
                    return(NextLevelResult);                        //如果下一層有回傳結果則代表是可行路徑則回傳下一層結果
                }
            }

            Board[Start] = 0; //如果上面迴圈沒有回傳則代表本層是失敗的,清除本層對盤面的影響
            return(null);     //回傳結果為空,因為下一步都無法走而為空值
        }
Esempio n. 4
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 public static GridBoard KnightTour(GridBoard Board) => KnightTour(Board, new Point());