/**==== Rule Disjunction
*
* The produce an `any` disjunction rule over many rules you can use the overloaded `|`
*/
[U] public void RulesDisjunction()
{
var anyRule = new UsernameRule("u1") | new UsernameRule("u2") | new UsernameRule("u3");
anyRule.Any.Should().NotBeEmpty().And.HaveCount(3);
/** using `|=` assignments you can build disjunction rules more dynamically **/
RoleMappingRuleBase rules = null;
for (var i = 0; i < 10; i++)
{
rules |= new UsernameRule($"user_{i}");
}
rules.Should().BeOfType <AnyRoleMappingRule>();
anyRule = (AnyRoleMappingRule)rules;
anyRule.Any.Should().NotBeEmpty().And.HaveCount(10);
}
/**==== Rule Conjunction
*
* You can create a conjuction of many rules using either `+` or `&` which are both overloaded to produce an `all` rule.
*/
[U] public void RulesConjunction()
{
var allRule = new UsernameRule("u1") + new UsernameRule("u2") & new UsernameRule("u3");
allRule.All.Should().NotBeEmpty().And.HaveCount(3);
/** using `+=` assignments you can build rules more dynamically **/
RoleMappingRuleBase rules = null;
for (var i = 0; i < 10; i++)
{
rules += new UsernameRule($"user_{i}");
}
rules.Should().BeOfType <AllRoleMappingRule>();
allRule = (AllRoleMappingRule)rules;
allRule.All.Should().NotBeEmpty().And.HaveCount(10);
}
