public static Line2D GetExtendLineWithIntersectPositions(Line2D line2D, Line2D[] extendLines, Vector2D[] intersectPositions, Rectangle2D2 rectIntersect)
{
if (extendLines.Length == 0)
{
return(null);
}
if (rectIntersect == null)
{
return(null);
}
if (intersectPositions.Length == 0)
{
return(null);
}
if (rectIntersect.Contains(line2D.Start) && rectIntersect.Contains(line2D.End) && intersectPositions.Length == 2)
{
var p1 = intersectPositions[0];
var p2 = intersectPositions[1];
if (line2D.Start.IsInLine(Line2D.Create(p1, line2D.End)))
{
return(Line2D.Create(p1, p2));
}
return(Line2D.Create(p2, p1));
}
if (rectIntersect.Contains(line2D.Start))
{
return(Line2D.Create(intersectPositions.First(), line2D.End));
}
if (rectIntersect.Contains(line2D.End))
{
return(Line2D.Create(line2D.Start, intersectPositions.First()));
}
return(null);
}
public override bool ObjectInRectangle(Rectangle2D2 rect, ICanvasScreenConvertable canvasProxy, bool anyPoint)
{
if (rect == null)
{
throw new ArgumentNullException(nameof(rect));
}
if (Ellipse2D == null)
{
return(false);
}
//无论是否为任意选中,若包含了,则能够选中;
if (rect.Contains(Ellipse2D.Center) && rect.GetLines().All(p => p.Distance(Ellipse2D.Center) >= Ellipse2D.RadiusX))
{
return(true);
}
//若为任意点选中,矩形的四个顶点中,存在任意两点任意一点在椭圆内即可;
if (anyPoint && rect.GetLines().Any(p => {
var intersectPoints = Extension.IntersectWithLine(Ellipse2D, p);
return((intersectPoints?.Length ?? 0) != 0);
}))
{
return(rect.GetVertexes().Any(p => Ellipse2D.Contains(p)));
}
return(false);
}
public static Line2D GetExtendMemberWithIntersectPositions(Line2D line2D, Line2D[] extendLines, Vector2D[] intersectPositions, Rectangle2D2 rectIntersect, double width, double gap)
{
if (extendLines.Length == 0)
{
return(null);
}
if (rectIntersect == null)
{
return(null);
}
if (intersectPositions.Length == 0)
{
return(null);
}
if (rectIntersect.Contains(line2D.Start) && rectIntersect.Contains(line2D.End) && intersectPositions.Length == 2)
{
var p1 = intersectPositions[0];
var p2 = intersectPositions[1];
var line1 = extendLines.First(x => p1.IsInLine(x));
var angle1 = line1.Direction.AngleWith(line2D.Direction);
var newP1 = GetExtendPoint(p1, -line2D.Direction, angle1, width, gap);
var line2 = extendLines.First(x => p2.IsInLine(x));
var angle2 = line2.Direction.AngleWith(line2D.Direction);
var newP2 = GetExtendPoint(p2, line2D.Direction, angle2, width, gap);
if (line2D.Start.IsInLine(Line2D.Create(p1, line2D.End)))
{
return(Line2D.Create(newP1, newP2));
}
return(Line2D.Create(newP2, newP1));
}
if (rectIntersect.Contains(line2D.Start) && line2D.Start.IsInLine(Line2D.Create(intersectPositions.First(), line2D.End)))
{
var angle = line2D.Direction.AngleWith(extendLines[0].Direction);
var newEndPoint = GetExtendPoint(intersectPositions.First(), -line2D.Direction, angle, width, gap);
return(Line2D.Create(newEndPoint, line2D.End));
}
if (rectIntersect.Contains(line2D.End) && line2D.End.IsInLine(Line2D.Create(intersectPositions.First(), line2D.Start)))
{
var angle = line2D.Direction.AngleWith(extendLines[0].Direction);
var newEndPoint = GetExtendPoint(intersectPositions.First(), line2D.Direction, angle, width, gap);
return(Line2D.Create(line2D.Start, newEndPoint));
}
return(null);
}
/// <summary>
/// 判断某个矩形与某个线段的包含或相交(当<paramref name="anyPoint"/>为真时)关系;
/// </summary>
/// <param name="line2D"></param>
/// <param name="rect"></param>
/// <param name="anyPoint"></param>
/// <returns></returns>
public static bool LineInRectangle(Line2D line2D, Rectangle2D2 rect, bool anyPoint)
{
if (line2D == null)
{
return(false);
}
//若在完全在矩形内部,则返回为真;
if (rect.Contains(line2D.Start) &&
rect.Contains(line2D.End))
{
return(true);
}
//若任意可选为真,则矩形任意一条边与之存在相交即可;
else if (anyPoint)
{
return(rect.GetLines()?.Any(p => p.Intersect(line2D) != null) ?? false);
}
return(false);
}
public override bool ObjectInRectangle(Rectangle2D2 rect, ICanvasScreenConvertable canvasProxy, bool anyPoint)
{
if (rect == null)
{
throw new ArgumentNullException(nameof(rect));
}
if (Rectangle2D == null)
{
return(false);
}
//根据四个顶点的位置判断与指定矩形的包含关系;
if (anyPoint)
{
return(Rectangle2D.GetVertexes()?.Any(p => rect.Contains(p)) ?? false);
}
else
{
return(Rectangle2D.GetVertexes()?.All(p => rect.Contains(p)) ?? false);
}
}
