public void Vector2DotTest2()
{
Vector2 a = new Vector2(Single.MinValue, Single.MinValue);
Vector2 b = new Vector2(Single.MaxValue, Single.MaxValue);
Single actual = Vector2.Dot(a, b);
Assert.True(Single.IsNegativeInfinity(actual), "Vector2f.Dot did not return the expected value.");
}
public void Vector2DotTest1()
{
Vector2 a = new Vector2(1.55f, 1.55f);
Vector2 b = new Vector2(-1.55f, 1.55f);
Single expected = 0.0f;
Single actual = Vector2.Dot(a, b);
Assert.Equal(expected, actual);
}
public void Vector2DotTest()
{
Vector2 a = new Vector2(1.0f, 2.0f);
Vector2 b = new Vector2(3.0f, 4.0f);
Single expected = 11.0f;
Single actual;
actual = Vector2.Dot(a, b);
Assert.True(MathHelper.Equal(expected, actual), "Vector2f.Dot did not return the expected value.");
}
public static Single DotJitOptimizeCanaryTest()
{
Single result = 0.0f;
var value = VectorTests.Vector2Value;
for (var iteration = 0; iteration < Benchmark.InnerIterationCount; iteration++)
{
value += VectorTests.Vector2Delta;
result += Vector2.Dot(value, VectorTests.Vector2ValueInverted);
}
return(result);
}
public static Single DotTest()
{
Single result = 0.0f;
for (var iteration = 0; iteration < Benchmark.InnerIterationCount; iteration++)
{
// The inputs aren't being changed and the output is being reset with each iteration, so a future
// optimization could potentially throw away everything except for the final call. This would break
// the perf test. The JitOptimizeCanary code below does modify the inputs and consume each output.
result = Vector2.Dot(VectorTests.Vector2Value, VectorTests.Vector2ValueInverted);
}
return(result);
}
