/// <summary>
/// Calculates the affine coordinates of a cross point of a infinitly line.
/// To calculate the cross point use: pt = A + (B - A) * Lam + (C - A) * mue
/// </summary>
/// <param name="L">Infinitly line</param>
/// <param name="Lam">affine coordinate relatively to (B - A)</param>
/// <param name="Mue">affine coordinate relatively to (C - A)</param>
/// <returns></returns>
public bool AffinCoordOfCross(LineType L, ref double Lam, ref double Mue)
{
Lam = 0;
Mue = 0;
Plane plane = this.GetPlane();
double dummy, a, b, c, d;
xyz P, AB, AC, AP;
plane.Cross(L, out dummy, out P);
AB = B - A;
AC = C - A;
AP = P - A;
a = AB.x; b = AC.x; c = AB.y; d = AC.y;
xyz Det = AB & AC;
xyz Det1 = AP & AB;
xyz Det2 = AP & AC;
if ((Det * plane.NormalUnit) < 0.0000000001)
{
return(false);
}
Lam = (Det2 * plane.NormalUnit / (Det * plane.NormalUnit));
Mue = -(Det1 * plane.NormalUnit / (Det * plane.NormalUnit));
xyz T = AB * Lam + AC * Mue;
if (AP.dist(T) > 0.0001)
{
}
return(true);
}