public static List <SimplifiedCircuit> toSimplifiedCir(List <List <Record> > cirlist) //transforms to List<list<Record>> to List <SimplifiedCircuit>
{
List <SimplifiedCircuit> simplCirList = new List <SimplifiedCircuit>();
for (int i = 0; i < cirlist.Count; i++)
{
SimplifiedCircuit sCir = new SimplifiedCircuit();
for (int j = 0; j < cirlist.ElementAt(i).Count; j++)
{
sCir.elements.Add(cirlist.ElementAt(i).ElementAt(j).getName());
int[] nodes = cirlist.ElementAt(i).ElementAt(j).getNodes();
for (int k = 0; k < 4; k++)
{
if (nodes[k] > 0)
{
sCir.initialNodes.Add(nodes[k]);
}
}
sCir.initialNodes.Distinct();
simplCirList.Add(sCir);
}
}
return(simplCirList);
}
/* This method finds parallel subcircuits in circuit.
* To reduce complexity, method checks only not sequential nodes.
* At first step method gets an array of not sequential circuits
* Then the List< List<Record>> is made. This list contains lists with elements which are connected in concrete not sequential node
* For example , List of nodes, which are connected to the 3_d node
* After that , in each list of nodes method tries to find sublist of elements, which are connected to the other not serial nodes
* If this sublist was found, that means it is parallel subcircuit.
* Then, struct SimplifiedCircuit is made from this
*/
public static List <SimplifiedCircuit> findParallelSubcir(List <Record> testcircuit)
{
List <SimplifiedCircuit> parallelCirs = new List <SimplifiedCircuit>();
int[] notSerial = Utils.getNotSerialNodes(testcircuit);
List <List <Record> > byNodes = new List <List <Record> >();
for (int i = 0; i < notSerial.Length; i++)
{
List <Record> byNode = getElementsByNode(testcircuit, notSerial[i]);
byNodes.Add(byNode);
}
for (int i = 0; i < notSerial.Length; i++)
{
for (int j = i + 1; j < notSerial.Length; j++)
{
List <Record> parallel = getElementsByNode(byNodes.ElementAt(i), notSerial[j]);
if (parallel.Count > 1)
{
SimplifiedCircuit cir = new SimplifiedCircuit();
cir.initialNodes.Add(notSerial[i]);
cir.initialNodes.Add(notSerial[j]);
for (int n = 0; n < parallel.Count; n++)
{
cir.elements.Add(parallel.ElementAt(n).getName());
byNodes.ElementAt(i).Remove(parallel.ElementAt(n));
byNodes.ElementAt(j).Remove(parallel.ElementAt(n));
}
parallelCirs.Add(cir);
}
}
}
return(parallelCirs);
}