/// <summary>
/// Calculates the largest dimension (width or height) of the terrain slice
/// enclosed by the bounding box if the terrain slice is rotated such that
/// the median direction is pointing upwards in world space. Currently only
/// works with restricted (total longitude <= 180°) bounding boxes.
/// </summary>
public static float LargestDimension(BoundingBox boundingBox, float radius = 1.0f)
{
float width, height, lat;
// If the latitudes are on opposite sides, then we need to
// calculate the width at the equator.
if (boundingBox[1] * boundingBox[3] < 0)
{
lat = 0.0f;
}
// Else, use the latitude closest to the equator to calculate the width.
else
{
lat = Mathf.Min(Mathf.Abs(boundingBox[1]), Mathf.Max(boundingBox[3]));
}
// Calculate the width.
width = Vector3.Distance(
CoordinateUtils.LatLonToPosition(new Vector2(lat, boundingBox[0]), radius),
CoordinateUtils.LatLonToPosition(new Vector2(lat, boundingBox[2]), radius)
);
// Height should be calculated at the median longitude.
float lon = (boundingBox[0] + boundingBox[2]) / 2;
// Calculate the height.
height = Vector3.Distance(
CoordinateUtils.LatLonToPosition(new Vector2(boundingBox[1], lon), radius),
CoordinateUtils.LatLonToPosition(new Vector2(boundingBox[3], lon), radius)
);
return(Mathf.Max(width, height));
}
public static Vector3 MedianDirection(BoundingBox boundingBox)
{
Vector2 medianLatLong = MedianLatLon(boundingBox);
return(CoordinateUtils.LatLonToDirection(medianLatLong));
}