public void SolveSudoku(char[][] source)
{
var board = new Board(source);
board.Fill(print: false);
board.Print(leaveInTheEnd: true);
}
private void combo_difficulty_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
if (solver.IfWin(buffer))
{
solver.Solve_Empty(tab = new int[9, 9], 0, 0);
}
combo_difficulty.IsEditable = false;
board.Hard_Clear(siatka, buffer);
board.Fill(siatka, tab, combo_difficulty.SelectedIndex, buffer);
}
public static void Main(string[] args)
{
Console.WriteLine("Enter a sudoku board line by line with comma seperated numbers, and a zero for an empty square: ");
string line = Console.ReadLine();//collects user input
int[] input = line.Split(',').Select(n => Convert.ToInt32(n)).ToArray();
Solved.Fill(input);
Game.Unsolved.Fill(input);
Solved.PrintBoard();
while (Solved.zeroes.Count() != 0)
{
int initial = Solved.zeroes.Count();
for (int i = 0; i < Solved.zeroes.Count(); i++)
{
int boardIndex = Solved.zeroes.ElementAt(i);
List <int> currPoss = PossList(boardIndex, Solved);
if (currPoss.Count() == 1 && Solved.zeroes.Contains(boardIndex))//if there is only one possible number for that cell, enter it
{
int num = currPoss.ElementAt(0);
Solved.Reconstruct(boardIndex, num);
}
else
{
/*return from zero list matching row, column, and square find unique possibility, implrement, repeat for squ and col
* In other words, if a row needs 3 numbers, and one of those numbers only has one place it could go,
* regardless of whether you record it as the only possible option or not, it must be the solution and is entered
*/
int row = boardIndex / 9;
int col = boardIndex % 9;
int squ = (3 * (row / 3)) + (col / 3);
int[] rowIndx = new int[9];
int[] colIndx = new int[9];
int[] squIndx = new int[9];
for (int a = 0; a < 9; a++)//populates the index lists for the current row and column
{
rowIndx[a] = (row * 9) + a;
colIndx[a] = col + (9 * a);
}
for (int c = 0; c < 3; c++)//populates the index lists for the current square
{
for (int d = 0; d < 3; d++)
{
squIndx[(c * 3) + (d)] = (((squ - squ % 3) + c) * 9) + ((squ % 3) * 3) + d;
}
}
List <int> zRow = new List <int>();//lists that will hold the indexes of all the empty or 'zero' values in the row column or square
List <int> zCol = new List <int>();
List <int> zSqu = new List <int>();
for (int iter = 0; iter < 9; iter++)//populates zero lists
{
int r1 = rowIndx[iter];
int c = colIndx[iter];
int s = squIndx[iter];
if (Solved.zeroes.Contains(r1))
{
zRow.Add(r1);
}
if (Solved.zeroes.Contains(c))
{
zCol.Add(c);
}
if (Solved.zeroes.Contains(s))
{
zSqu.Add(s);
}
}
IndexLogic(zRow);//applies aforementioned logic through the IndexLogic function to the applicable row, column, and square
IndexLogic(zCol);
IndexLogic(zSqu);
}
}
if (initial == Solved.zeroes.Count())
{
Console.WriteLine("true"); break;
}
}
Console.WriteLine("Do you wish to solve the puzzle (y/n)?: ");//sets up to pass control over to Game to run the play
if (Console.ReadLine() == "y")
{
Game.Play();
}
else
{
Solved.PrintBoard();
}
Console.Read();
}
