MkBVSub() public méthode

Two's complement subtraction.
The arguments must have the same bit-vector sort.
public MkBVSub ( BitVecExpr t1, BitVecExpr t2 ) : BitVecExpr
t1 BitVecExpr
t2 BitVecExpr
Résultat BitVecExpr
Exemple #1
0
    public void Run()
    {
        Dictionary<string, string> cfg = new Dictionary<string, string>() {
            { "AUTO_CONFIG", "true" } };

        using (Context ctx = new Context(cfg))
        {
            BitVecExpr x = ctx.MkBVConst("x", 32);
            BitVecExpr[] powers = new BitVecExpr[32];
            for (uint i = 0; i < 32; i++)
                powers[i] = ctx.MkBVSHL(ctx.MkBV(1, 32), ctx.MkBV(i, 32));

            BoolExpr step_zero = ctx.MkEq(ctx.MkBVAND(x, ctx.MkBVSub(x, ctx.MkBV(1, 32))), ctx.MkBV(0, 32));

            BoolExpr fast = ctx.MkAnd(ctx.MkNot(ctx.MkEq(x, ctx.MkBV(0, 32))),
                                      step_zero);

            BoolExpr slow = ctx.MkFalse();
            foreach (BitVecExpr p in powers)
                slow = ctx.MkOr(slow, ctx.MkEq(x, p));

        TestDriver.CheckString(fast, "(and (not (= x #x00000000)) (= (bvand x (bvsub x #x00000001)) #x00000000))");

            Solver s = ctx.MkSolver();
            s.Assert(ctx.MkNot(ctx.MkEq(fast, slow)));
            TestDriver.CheckUNSAT(s.Check());

            s = ctx.MkSolver();
            s.Assert(ctx.MkNot(step_zero));
            TestDriver.CheckSAT(s.Check());
        }
    }
Exemple #2
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        /// <summary>
        /// Simple bit-vector example.
        /// </summary>
        /// <remarks>
        /// This example disproves that x - 10 &lt;= 0 IFF x &lt;= 10 for (32-bit) machine integers
        /// </remarks>
        public static void BitvectorExample1()
        {
            var ctx = new Z3.Context();

            using var svc = Z3Api.Own(ctx);


            var        bv_type     = ctx.MkBitVecSort(32);
            var        x           = (BitVecExpr)ctx.MkConst("x", bv_type);
            var        zero        = (BitVecNum)ctx.MkNumeral("0", bv_type);
            BitVecNum  ten         = ctx.MkBV(10, 32);
            BitVecExpr x_minus_ten = ctx.MkBVSub(x, ten);
            /* bvsle is signed less than or equal to */
            BoolExpr c1  = ctx.MkBVSLE(x, ten);
            BoolExpr c2  = ctx.MkBVSLE(x_minus_ten, zero);
            BoolExpr thm = ctx.MkIff(c1, c2);

            print("disprove: x - 10 <= 0 IFF x <= 10 for (32-bit) machine integers");
            Disprove(ctx, thm);
        }
Exemple #3
0
    public void Run()
    {
        Dictionary<string, string> cfg = new Dictionary<string, string>() {
            { "AUTO_CONFIG", "true" } };

        using (Context ctx = new Context(cfg))
        {
            BitVecExpr x = ctx.MkBVConst("x", 16);
            BitVecExpr y = ctx.MkBVConst("y", 16);

            Console.WriteLine(ctx.MkBVAdd(x, ctx.MkBV(2, 16)));

            Console.WriteLine(ctx.MkBVSub(ctx.MkBVAdd(x, y), ctx.MkBV(1, 16)).Simplify());

            BitVecExpr a = ctx.MkBV(-1, 16);
            BitVecExpr b = ctx.MkBV(65535, 16);
            Console.WriteLine(ctx.MkEq(a, b).Simplify());

            a = ctx.MkBV(-1, 32);
            b = ctx.MkBV(65535, 32);
            Console.WriteLine(ctx.MkEq(a, b).Simplify());
        }
    }
Exemple #4
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        /// <summary>
        /// Find x and y such that: x ^ y - 103 == x * y
        /// </summary>
        public static void BitvectorExample2(Context ctx)
        {
            Console.WriteLine("BitvectorExample2");

            /* construct x ^ y - 103 == x * y */
            Sort bv_type = ctx.MkBitVecSort(32);
            BitVecExpr x = ctx.MkBVConst("x", 32);
            BitVecExpr y = ctx.MkBVConst("y", 32);
            BitVecExpr x_xor_y = ctx.MkBVXOR(x, y);
            BitVecExpr c103 = (BitVecNum)ctx.MkNumeral("103", bv_type);
            BitVecExpr lhs = ctx.MkBVSub(x_xor_y, c103);
            BitVecExpr rhs = ctx.MkBVMul(x, y);
            BoolExpr ctr = ctx.MkEq(lhs, rhs);

            Console.WriteLine("find values of x and y, such that x ^ y - 103 == x * y");

            /* find a model (i.e., values for x an y that satisfy the constraint */
            Model m = Check(ctx, ctr, Status.SATISFIABLE);
            Console.WriteLine(m);
        }
Exemple #5
0
        /// <summary>
        /// Simple bit-vector example.
        /// </summary>
        /// <remarks>
        /// This example disproves that x - 10 &lt;= 0 IFF x &lt;= 10 for (32-bit) machine integers
        /// </remarks>
        public static void BitvectorExample1(Context ctx)
        {
            Console.WriteLine("BitvectorExample1");

            Sort bv_type = ctx.MkBitVecSort(32);
            BitVecExpr x = (BitVecExpr)ctx.MkConst("x", bv_type);
            BitVecNum zero = (BitVecNum)ctx.MkNumeral("0", bv_type);
            BitVecNum ten = ctx.MkBV(10, 32);
            BitVecExpr x_minus_ten = ctx.MkBVSub(x, ten);
            /* bvsle is signed less than or equal to */
            BoolExpr c1 = ctx.MkBVSLE(x, ten);
            BoolExpr c2 = ctx.MkBVSLE(x_minus_ten, zero);
            BoolExpr thm = ctx.MkIff(c1, c2);
            Console.WriteLine("disprove: x - 10 <= 0 IFF x <= 10 for (32-bit) machine integers");
            Disprove(ctx, thm);
        }