private void InitPosition(SyntaxTree tree, TextSpan span)
{
var x = tree.GetLineSpan(span);
this._line = x.StartLinePosition.Line + 1;
this._column = x.StartLinePosition.Character + 1;
this._endLine = x.EndLinePosition.Line + 1;
this._endColumn = x.EndLinePosition.Character + 1;
}
protected override IEnumerable<string> ReportAllErrors(SyntaxTree userSolution)
{
var text = userSolution.GetText();
var longLines = text.Lines.Where(line => line.End - line.Start > maxLineLen).ToList();
if (longLines.Count == 0) yield break;
var position = userSolution.GetLineSpan(longLines[0].Span);
yield return Report(
position,
"Слишком длинная строка. Не заставляйте людей использовать горизонтальный скролл");
}
public override FileLinePositionSpan GetLineSpan()
{
// If there's no syntax tree (e.g. because we're binding speculatively),
// then just return an invalid span.
if (_syntaxTree == null)
{
FileLinePositionSpan result = default(FileLinePositionSpan);
Debug.Assert(!result.IsValid);
return(result);
}
return(_syntaxTree.GetLineSpan(_span));
}
private static int GetIndentationSteps(IndentationSettings indentationSettings, SyntaxTree syntaxTree, SyntaxTriviaList leadingTrivia)
{
var triviaSpan = syntaxTree.GetLineSpan(leadingTrivia.FullSpan);
// There is no indentation when the leading trivia doesn't begin at the start of the line.
if ((triviaSpan.StartLinePosition == triviaSpan.EndLinePosition) && (triviaSpan.StartLinePosition.Character > 0))
{
return 0;
}
var builder = StringBuilderPool.Allocate();
foreach (SyntaxTrivia trivia in leadingTrivia.Reverse())
{
if (!trivia.IsKind(SyntaxKind.WhitespaceTrivia))
{
break;
}
builder.Insert(0, trivia.ToFullString());
}
var tabSize = indentationSettings.TabSize;
var indentationCount = 0;
for (var i = 0; i < builder.Length; i++)
{
indentationCount += builder[i] == '\t' ? tabSize - (indentationCount % tabSize) : 1;
}
StringBuilderPool.ReturnAndFree(builder);
return (indentationCount + (indentationSettings.IndentationSize / 2)) / indentationSettings.IndentationSize;
}
public CompleterError(SyntaxTree tree, Message message, SyntaxToken token)
: this(tree, message, tree.GetLineSpan(token.Span))
{
}
private int GetStartLinePosition(SyntaxTree syntaxTree, TextSpan textSpan)
{
return syntaxTree.GetLineSpan(textSpan).StartLinePosition.Line;
}