// 128. Longest Consecutive Sequence
// A small tweak on UnionFind to add the FindSize method for this problem
public int LongestConsecutive(int[] nums)
{
var uf = new UnionFind(nums.Length);
var dict = new Dictionary <int, int>();
var maxLength = 0;
for (int i = 0; i < nums.Length; i++)
{
if (!dict.ContainsKey(nums[i]))
{
dict.Add(nums[i], i);
}
else
{
continue;
}
if (dict.ContainsKey(nums[i] - 1))
{
uf.Union(i, dict[nums[i] - 1]);
}
if (dict.ContainsKey(nums[i] + 1))
{
uf.Union(i, dict[nums[i] + 1]);
}
maxLength = Math.Max(maxLength, uf.FindSize(i));
}
return(maxLength);
}
// 695. Max Area of Island
public int MaxAreaOfIsland(int[][] grid)
{
var m = grid.Length;
var n = grid[0].Length;
var totalLength = m * n;
var uf = new UnionFind(totalLength + 1);
var maxArea = 0;
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
if (grid[i][j] == 0)
{
uf.Union(i * n + j, totalLength);
}
else
{
if (j + 1 < n && grid[i][j + 1] == 1)
{
uf.Union(i * n + j, i * n + j + 1);
}
if (i + 1 < m && grid[i + 1][j] == 1)
{
uf.Union((i + 1) * n + j, i * n + j);
}
maxArea = Math.Max(maxArea, uf.FindSize(i * n + j));
}
}
}
return(maxArea);
}
// Union Find solution
// great solution
public int NumIslands2(char[][] grid)
{
var m = grid.Length;
var n = grid[0].Length;
var totalLength = m * n;
var uf = new UnionFind(totalLength + 1);
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
if (grid[i][j] == '1')
{
if (j + 1 < n && grid[i][j + 1] == '1')
{
uf.Union(i * n + j, i * n + j + 1);
}
if (i + 1 < m && grid[i + 1][j] == '1')
{
uf.Union(i * n + j, (i + 1) * n + j);
}
}
else
{
uf.Union(i * n + j, totalLength);
}
}
}
return(uf.Count() - 1);
}
public int CalculateEnclosedArea(int[][] grid)
{
var m = grid.Length;
var n = grid[0].Length;
var totalCells = m * n;
var uf = new UnionFind(totalCells + 3);
// uf[totalCells] -> 0 cell that is not enclosed,
// uf[totalCells + 1] -> wall cells(value >= 1),
// uf[totalCells + 2] -> enclosed 0 cells
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
if (grid[i][j] > 0)
{
uf.Union(i * n + j, totalCells + 1);
}
if (grid[i][j] == 0)
{
if (i == 0 || j == 0 || i == m - 1 || j == n - 1)
{
uf.Union(i * n + j, totalCells);
}
if (i + 1 < m && grid[i + 1][j] == 0)
{
uf.Union(i * n + j, (i + 1) * n + j);
}
if (j + 1 < n && grid[i][j + 1] == 0)
{
uf.Union(i * n + j, i * n + j + 1);
}
}
}
}
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
if (grid[i][j] == 0 && !uf.Connected(i * n + j, totalCells))
{
uf.Union(i * n + j, totalCells + 2);
}
}
}
return(uf.FindSize(totalCells + 2) - 1);
}
// 261. Graph Valid Tree
// Ridiculously easy with UnionFind
public bool ValidTree(int n, int[][] edges)
{
var uf = new UnionFind(n);
foreach (var e in edges)
{
if (uf.Connected(e[0], e[1]))
{
return(false);
}
uf.Union(e[0], e[1]);
}
return(uf.Count() == 1);
}
// 990. Satisfiability of Equality Equations
// This solution is super easy and mathmatically brilliant with the usage of Union-Find
public bool EquationsPossible(string[] equations)
{
var uf = new UnionFind(26);
foreach (var eq in equations)
{
if (eq.Substring(1, 2) == "==")
{
uf.Union(eq[0] - 'a', eq[3] - 'a');
}
}
foreach (var eq in equations)
{
if (eq.Substring(1, 2) == "!=")
{
if (uf.Connected(eq[0] - 'a', eq[3] - 'a'))
{
return(false);
}
}
}
return(true);
}
// 130. Surrounded Regions
// This solution with Union-find, very hard-core algorithm
public void Solve(char[][] board)
{
var m = board.Length;
var n = board[0].Length;
var totalLength = m * n;
var uf = new UnionFind(totalLength + 1); // one extra cell for initial connectivity
// input perimeter cells
for (int i = 0; i < n; i++)
{
if (board[0][i] == 'O')
{
uf.Union(i, totalLength);
}
if (board[m - 1][i] == 'O')
{
uf.Union((m - 1) * n + i, totalLength);
}
}
for (int j = 0; j < m; j++)
{
if (board[j][0] == 'O')
{
uf.Union(j * n, totalLength);
}
if (board[j][n - 1] == 'O')
{
uf.Union(j * n + n - 1, totalLength);
}
}
for (int x = 0; x < m; x++)
{
for (int y = 0; y < n; y++)
{
if (board[x][y] != 'O')
{
continue;
}
if (x - 1 >= 0 && board[x - 1][y] == 'O')
{
uf.Union(x * n + y, (x - 1) * n + y);
}
if (x + 1 < m && board[x + 1][y] == 'O')
{
uf.Union(x * n + y, (x + 1) * n + y);
}
if (y - 1 >= 0 && board[x][y - 1] == 'O')
{
uf.Union(x * n + y, x * n + y - 1);
}
if (y + 1 < n && board[x][y + 1] == 'O')
{
uf.Union(x * n + y, x * n + y + 1);
}
}
}
for (int x = 1; x < m - 1; x++)
{
for (int y = 1; y < n - 1; y++)
{
if (board[x][y] == 'O' && !uf.Connected(x * n + y, totalLength))
{
board[x][y] = 'X';
}
}
}
}
