Exemple #1
0
        //中级难度算式构造,包含加、减、乘的任意两个,当结果出现负号时,用括号将结果纠正
        private static string CMediumFormula(int[] opds, char[] ops)
        {
            string formula = null;

            char op1 = ops[ran.Next(0, 3)];
            char op2 = ops[ran.Next(0, 3)];

            if (op1 == '-')
            {
                CompareAndChange(ref opds[0], ref opds[1]);
            }

            formula = opds[0].ToString() + op1 + opds[1].ToString() + op2 + opds[2].ToString();

            if (CalculatorCore.Calculate(formula) < 0)
            {
                if (op1 == '-')
                {
                    CompareAndChange(ref opds[0], ref opds[1]);
                    formula = "(" + opds[0].ToString() + op1 + opds[1].ToString() + ")" + op2 + opds[2].ToString();
                    if (CalculatorCore.Calculate(formula) < 0)
                    {
                        formula = opds[2].ToString() + op2 + "(" + opds[0].ToString() + op1 + opds[1].ToString() + ")";
                    }
                }
                else
                {
                    CompareAndChange(ref opds[1], ref opds[2]);
                    formula = opds[0].ToString() + op1 + "(" + opds[1].ToString() + op2 + opds[2].ToString() + ")";
                }
            }

            return(formula);
        }
Exemple #2
0
        //高级难度算式构造,整数与分数、分数与分数的混合运算
        private static string CDifficultFormula(int[] opds, char[] ops, ref string num)
        {
            string   formula = null;
            Fraction fraction1;
            Fraction fraction2;

            char op = ops[ran.Next(0, 3)];

            CompareAndChange(ref opds[0], ref opds[1]);
            fraction1 = new Fraction(opds[1], opds[0]);
            Simplify(ref fraction1);

            CompareAndChange(ref opds[2], ref opds[3]);
            fraction2 = new Fraction(opds[3], opds[2]);
            Simplify(ref fraction2);


            if (0 == ran.Next(1, 100) % 2)//余数为0,分数与整数运算,为1,分数与分数运算
            {
                formula = fraction1.ToString() + op + opds[2].ToString();
                num     = FractionCalculator(fraction1, op, new Fraction(opds[2], 1)).ToString();
                if (CalculatorCore.Calculate(formula) < 0)
                {
                    formula = opds[2].ToString() + op + fraction1.ToString();
                    num     = FractionCalculator(new Fraction(opds[2], 1), op, fraction1).ToString();
                }
            }
            else
            {
                formula = fraction1.ToString() + op + fraction2;
                num     = FractionCalculator(fraction1, op, fraction2).ToString();
                if (CalculatorCore.Calculate(formula) < 0)
                {
                    formula = fraction2.ToString() + op + fraction1.ToString();
                    num     = FractionCalculator(fraction2, op, fraction1).ToString();
                }
            }

            return(formula);
        }
Exemple #3
0
        static Random ran = new Random(GetRandomSeed()); //产生不重复的随机数

        //生成算式,complexity表示题的难易程度,范围(0、1、2)
        public static string CreateFormula(int complexity)
        {
            string formula;

            char[] operators = { '+', '-', '*', '/' };
            int[]  operands  = new int[4];
            string num       = null;

            for (int i = 0; i < operands.Length; i++)
            {
                operands[i] = ran.Next(1, 100);//构造四个操作数
                if (i > 0)
                {
                    while (operands[i] == operands[i - 1])
                    {
                        operands[i] = ran.Next(1, 100);//确保操作数不相同
                    }
                }
            }

            if (0 == complexity)
            {
                formula = CEasyFormula(operands, operators);
                num     = CalculatorCore.Calculate(formula).ToString();//计算算式的结果
            }
            else if (1 == complexity)
            {
                formula = CMediumFormula(operands, operators);
                num     = CalculatorCore.Calculate(formula).ToString();//计算算式的结果
            }
            else
            {
                formula = CDifficultFormula(operands, operators, ref num);
            }



            return(formula + "=" + num);
        }