private IList <string> CreateListOfProperlyOrderedNames(XmlElement element, IList <MessagePart> messagePartAndChoiceExtensionParts
, MessageVisitor visitor)
{
IList <string> properlyOrderedProvidedRelationshipNames = new List <string>();
foreach (MessagePart messagePart in messagePartAndChoiceExtensionParts)
{
ElementBridge helper = new ElementBridge(element, messagePart, GetInteraction(element.OwnerDocument));
foreach (RelationshipBridge relationshipBridge in helper.GetRelationships())
{
if (!relationshipBridge.IsStructuralAttribute())
{
ICollection <string> names = relationshipBridge.GetNames();
if (!names.IsEmpty())
{
IEnumerator <string> iterator = names.GetEnumerator();
if (iterator.MoveNext())
{
//For .NET translation
properlyOrderedProvidedRelationshipNames.Add(iterator.Current);
}
if (names.Count > 1)
{
// not expecting this to ever happen, but need to know if it does so we can adjust the code
visitor.AddError("Internal error: found more than one name " + ListNames(names), element);
}
}
}
}
}
return(properlyOrderedProvidedRelationshipNames);
}
private void ProcessAllRelationships(XmlElement element, Interaction interaction, IList <MessagePart> messagePartAndChoiceExtensionParts
, MessageVisitor visitor)
{
ICollection <string> knownItems = new HashSet <string>();
ValidateElementOrder(messagePartAndChoiceExtensionParts, element, visitor);
foreach (MessagePart messagePart in messagePartAndChoiceExtensionParts)
{
ElementBridge helper = new ElementBridge(element, messagePart, GetInteraction(element.OwnerDocument));
foreach (RelationshipBridge relationship in helper.GetRelationships())
{
knownItems.AddAll(relationship.GetNames());
ProcessRelationship(interaction, messagePart, relationship, visitor);
}
}
ProcessUnknownStructuralAttributes(new HashSet <string>(knownItems), element, visitor);
ProcessUnknownChildElements(new HashSet <string>(knownItems), element, visitor);
}
public RelationshipBridge(ElementBridge elementBridge, Relationship relationship)
{
this.elementBridge = elementBridge;
this.relationship = relationship;
}
