private void Form1_Load(object sender, EventArgs e) { BigInt b1 = dividend; BigInt b2 = divisor; BigInt b3 = b1 / b2; if (b3 > 2147483647 || b3 < -2147483648) { b3 = -2147483648; } return(Convert.ToInt32(b3.ToString())); BigInt bigInt1 = 1; //给以解决LeetCode上大量数字类问题 for (int i = 1; i < 10000; i++) { bigInt1 *= 2; } }