/// <summary>
/// A noise with multiple octaves has abominated value (the more octaves, the higher),
/// so we have to find out the modifiers that would normalize the values again. In order
/// not to calculate it for each possible persistence, we do it for 10 values of persistence
/// and then will use approximations.
/// </summary>
private static Dictionary <int, float> InitializeAfterNoiseAdjustments(int octaves)
{
var dictionary = new Dictionary <int, float>();
for (int i = 0; i <= 10; i += 1)
{
float persistence = ((float)i) / 10;
float maxValueFromNoise = Perlin.MaxValueFromNoise(octaves, persistence: persistence);
float maxValueFromNoiseInverted = 1 / maxValueFromNoise;
dictionary[i] = maxValueFromNoiseInverted;
}
return(dictionary);
}