/// <summary>
/// Emit the PhpType finalizer. The finalizer is emitted only if there is __destruct() function
/// and there is no finalizer in any base class already. The finalizer calls this.Dispose() which
/// calls __destruct() function directly.
/// </summary>
/// <param name="phpType"></param>
private static void EmitFinalizer(PhpType /*!*/ phpType)
{
// only if __destruct was now defined in some base class, no need to override existing definition on Finalize
DRoutine basedestruct;
DRoutineDesc destruct;
if ((destruct = phpType.TypeDesc.GetMethod(DObject.SpecialMethodNames.Destruct)) != null && (phpType.Base == null ||
phpType.Base.GetMethod(DObject.SpecialMethodNames.Destruct, phpType, out basedestruct) == GetMemberResult.NotFound))
{
MethodBuilder finalizer_builder = phpType.RealTypeBuilder.DefineMethod("Finalize", MethodAttributes.HideBySig | MethodAttributes.Virtual | MethodAttributes.Family, typeof(void), Type.EmptyTypes);
ILEmitter dil = new ILEmitter(finalizer_builder);
// exact Finalize() method pattern follows:
// try
dil.BeginExceptionBlock();
// this.Dispose(false)
dil.Emit(OpCodes.Ldarg_0);
dil.Emit(OpCodes.Ldc_I4_0);
dil.Emit(OpCodes.Callvirt, PHP.Core.Emit.Methods.DObject_Dispose);
// finally
dil.BeginFinallyBlock();
// Object.Finalize()
dil.Emit(OpCodes.Ldarg_0);
dil.Emit(OpCodes.Call, PHP.Core.Emit.Methods.Object_Finalize);
dil.EndExceptionBlock();
dil.Emit(OpCodes.Ret);
}
}