/// <summary>
/// If the current calculator for the <typeparamref name="T"/> type does not support conversions
/// from the double type AND the <paramref name="num"/> does not exceed the range of long,
/// this method will result in smaller number of exceptions, because
/// if <paramref name="num"/> value contains only integral part, the 'fromInt(int)' calculator method
/// will be preferred over the 'fromDouble(double)'.
/// </summary>
/// <typeparam name="T">The type of numbers for the calculator.</typeparam>
/// <param name="calculator">The calling calculator object.</param>
/// <param name="num">The number which is to be converted to the <typeparamref name="T"/> type.</param>
/// <returns>The <typeparamref name="T"/> value returned by either fromInt (preferred) of fromDouble calculator method.</returns>
public static T fromDoubleSafe <T>(this ICalc <T> calculator, double num)
{
if (Numeric <double, CalcDouble> .Calculator.fracPart(num) == 0 && num > long.MinValue && num < long.MaxValue)
{
return(calculator.fromInt((long)num));
}
return(calculator.fromDouble(num));
}
