private void btnUpload_Click(object sender, EventArgs e) { OpenFileDialog opFilDlg = new OpenFileDialog(); if (opFilDlg.ShowDialog() == DialogResult.OK) { client.UploadFile(opFilDlg.FileName); } }
private void button6_Click(object sender, EventArgs e) { client.UploadFile(textBox6.Text, textBox7.Text); }