private void pictureBox4_Click(object sender, EventArgs e)
        {
            menu m = new menu();

            m.Show();
            this.Hide();
        }
Example #2
0
        private void button1_Click(object sender, EventArgs e)
        {
            /*  try
             * {
             *    MySqlConnection cn = new MySqlConnection("server=localhost;user id=root;database=projectdatabase;pwd=rohan!@#");
             *    cn.Open();
             *
             *
             * }
             * catch (Exception ex)
             * { MessageBox.Show("Connection failed\n" + ex.Message); }*/
            menu a = new menu();

            a.Show();
            this.Visible = false;
        }