/// <summary>
/// Add a bad triangle to the end of a queue.
/// </summary>
/// <param name="enqtri"></param>
/// <param name="minedge"></param>
/// <param name="apex"></param>
/// <param name="org"></param>
/// <param name="dest"></param>
public void Enqueue(ref Otri enqtri, float minedge, Vertex apex, Vertex org, Vertex dest)
{
// Allocate space for the bad triangle.
BadTriangle newbad = new BadTriangle();
newbad.poortri = enqtri;
newbad.key = minedge;
newbad.apex = apex;
newbad.org = org;
newbad.dest = dest;
Enqueue(newbad);
}
/// <summary>
/// Remove a triangle from the front of the queue.
/// </summary>
/// <returns></returns>
public BadTriangle Dequeue()
{
// If no queues are nonempty, return NULL.
if (firstnonemptyq < 0)
{
return(null);
}
count--;
// Find the first triangle of the highest-priority queue.
BadTriangle result = queuefront[firstnonemptyq];
// Remove the triangle from the queue.
queuefront[firstnonemptyq] = result.next;
// If this queue is now empty, note the new highest-priority
// nonempty queue.
if (result == queuetail[firstnonemptyq])
{
firstnonemptyq = nextnonemptyq[firstnonemptyq];
}
return(result);
}
/// <summary>
/// Inserts a vertex at the circumcenter of a triangle. Deletes
/// the newly inserted vertex if it encroaches upon a segment.
/// </summary>
/// <param name="badtri"></param>
private void SplitTriangle(BadTriangle badtri)
{
Otri badotri = default(Otri);
Vertex borg, bdest, bapex;
Point newloc; // Location of the new vertex
double xi = 0, eta = 0;
InsertVertexResult success;
bool errorflag;
badotri = badtri.poortri;
borg = badotri.Org();
bdest = badotri.Dest();
bapex = badotri.Apex();
// Make sure that this triangle is still the same triangle it was
// when it was tested and determined to be of bad quality.
// Subsequent transformations may have made it a different triangle.
if (!Otri.IsDead(badotri.tri) && (borg == badtri.org) &&
(bdest == badtri.dest) && (bapex == badtri.apex))
{
errorflag = false;
// Create a new vertex at the triangle's circumcenter.
// Using the original (simpler) Steiner point location method
// for mesh refinement.
// TODO: NewLocation doesn't work for refinement. Why? Maybe
// reset VertexType?
if (behavior.fixedArea || behavior.VarArea)
{
newloc = predicates.FindCircumcenter(borg, bdest, bapex, ref xi, ref eta, behavior.offconstant);
}
else
{
newloc = newLocation.FindLocation(borg, bdest, bapex, ref xi, ref eta, true, badotri);
}
// Check whether the new vertex lies on a triangle vertex.
if (((newloc.x == borg.x) && (newloc.y == borg.y)) ||
((newloc.x == bdest.x) && (newloc.y == bdest.y)) ||
((newloc.x == bapex.x) && (newloc.y == bapex.y)))
{
if (Log.Verbose)
{
logger.Warning("New vertex falls on existing vertex.", "Quality.SplitTriangle()");
errorflag = true;
}
}
else
{
// The new vertex must be in the interior, and therefore is a
// free vertex with a marker of zero.
Vertex newvertex = new Vertex(newloc.x, newloc.y, 0
#if USE_ATTRIBS
, mesh.nextras
#endif
);
newvertex.type = VertexType.FreeVertex;
// Ensure that the handle 'badotri' does not represent the longest
// edge of the triangle. This ensures that the circumcenter must
// fall to the left of this edge, so point location will work.
// (If the angle org-apex-dest exceeds 90 degrees, then the
// circumcenter lies outside the org-dest edge, and eta is
// negative. Roundoff error might prevent eta from being
// negative when it should be, so I test eta against xi.)
if (eta < xi)
{
badotri.Lprev();
}
// Assign triangle for attributes interpolation.
newvertex.tri.tri = newvertex_tri;
// Insert the circumcenter, searching from the edge of the triangle,
// and maintain the Delaunay property of the triangulation.
Osub tmp = default(Osub);
success = mesh.InsertVertex(newvertex, ref badotri, ref tmp, true, true);
if (success == InsertVertexResult.Successful)
{
newvertex.hash = mesh.hash_vtx++;
newvertex.id = newvertex.hash;
#if USE_ATTRIBS
if (mesh.nextras > 0)
{
Interpolation.InterpolateAttributes(newvertex, newvertex.tri.tri, mesh.nextras);
}
#endif
mesh.vertices.Add(newvertex.hash, newvertex);
if (mesh.steinerleft > 0)
{
mesh.steinerleft--;
}
}
else if (success == InsertVertexResult.Encroaching)
{
// If the newly inserted vertex encroaches upon a subsegment,
// delete the new vertex.
mesh.UndoVertex();
}
else if (success == InsertVertexResult.Violating)
{
// Failed to insert the new vertex, but some subsegment was
// marked as being encroached.
}
else
{ // success == DUPLICATEVERTEX
// Couldn't insert the new vertex because a vertex is already there.
if (Log.Verbose)
{
logger.Warning("New vertex falls on existing vertex.", "Quality.SplitTriangle()");
errorflag = true;
}
}
}
if (errorflag)
{
logger.Error("The new vertex is at the circumcenter of triangle: This probably "
+ "means that I am trying to refine triangles to a smaller size than can be "
+ "accommodated by the finite precision of floating point arithmetic.",
"Quality.SplitTriangle()");
throw new Exception("The new vertex is at the circumcenter of triangle.");
}
}
}
/// <summary>
/// Add a bad triangle data structure to the end of a queue.
/// </summary>
/// <param name="badtri">The bad triangle to enqueue.</param>
public void Enqueue(BadTriangle badtri)
{
float length, multiplier;
int exponent, expincrement;
int queuenumber;
int posexponent;
int i;
count++;
// Determine the appropriate queue to put the bad triangle into.
// Recall that the key is the square of its shortest edge length.
if (badtri.key >= 1.0f)
{
length = badtri.key;
posexponent = 1;
}
else
{
// 'badtri.key' is 2.0 to a negative exponent, so we'll record that
// fact and use the reciprocal of 'badtri.key', which is > 1.0.
length = 1.0f / badtri.key;
posexponent = 0;
}
// 'length' is approximately 2.0 to what exponent? The following code
// determines the answer in time logarithmic in the exponent.
exponent = 0;
while (length > 2.0f)
{
// Find an approximation by repeated squaring of two.
expincrement = 1;
multiplier = 0.5f;
while (length * multiplier * multiplier > 1.0f)
{
expincrement *= 2;
multiplier *= multiplier;
}
// Reduce the value of 'length', then iterate if necessary.
exponent += expincrement;
length *= multiplier;
}
// 'length' is approximately squareroot(2.0) to what exponent?
exponent = 2 * exponent + (length > SQRT2 ? 1 : 0);
// 'exponent' is now in the range 0...2047 for IEEE float precision.
// Choose a queue in the range 0...4095. The shortest edges have the
// highest priority (queue 4095).
if (posexponent > 0)
{
queuenumber = 2047 - exponent;
}
else
{
queuenumber = 2048 + exponent;
}
// Are we inserting into an empty queue?
if (queuefront[queuenumber] == null)
{
// Yes, we are inserting into an empty queue.
// Will this become the highest-priority queue?
if (queuenumber > firstnonemptyq)
{
// Yes, this is the highest-priority queue.
nextnonemptyq[queuenumber] = firstnonemptyq;
firstnonemptyq = queuenumber;
}
else
{
// No, this is not the highest-priority queue.
// Find the queue with next higher priority.
i = queuenumber + 1;
while (queuefront[i] == null)
{
i++;
}
// Mark the newly nonempty queue as following a higher-priority queue.
nextnonemptyq[queuenumber] = nextnonemptyq[i];
nextnonemptyq[i] = queuenumber;
}
// Put the bad triangle at the beginning of the (empty) queue.
queuefront[queuenumber] = badtri;
}
else
{
// Add the bad triangle to the end of an already nonempty queue.
queuetail[queuenumber].next = badtri;
}
// Maintain a pointer to the last triangle of the queue.
queuetail[queuenumber] = badtri;
// Newly enqueued bad triangle has no successor in the queue.
badtri.next = null;
}
/// <summary>
/// Add a bad triangle data structure to the end of a queue.
/// </summary>
/// <param name="badtri">The bad triangle to enqueue.</param>
public void Enqueue(BadTriangle badtri)
{
double length, multiplier;
int exponent, expincrement;
int queuenumber;
int posexponent;
int i;
this.count++;
// Determine the appropriate queue to put the bad triangle into.
// Recall that the key is the square of its shortest edge length.
if (badtri.key >= 1.0)
{
length = badtri.key;
posexponent = 1;
}
else
{
// 'badtri.key' is 2.0 to a negative exponent, so we'll record that
// fact and use the reciprocal of 'badtri.key', which is > 1.0.
length = 1.0 / badtri.key;
posexponent = 0;
}
// 'length' is approximately 2.0 to what exponent? The following code
// determines the answer in time logarithmic in the exponent.
exponent = 0;
while (length > 2.0)
{
// Find an approximation by repeated squaring of two.
expincrement = 1;
multiplier = 0.5;
while (length * multiplier * multiplier > 1.0)
{
expincrement *= 2;
multiplier *= multiplier;
}
// Reduce the value of 'length', then iterate if necessary.
exponent += expincrement;
length *= multiplier;
}
// 'length' is approximately squareroot(2.0) to what exponent?
exponent = 2 * exponent + (length > SQRT2 ? 1 : 0);
// 'exponent' is now in the range 0...2047 for IEEE double precision.
// Choose a queue in the range 0...4095. The shortest edges have the
// highest priority (queue 4095).
if (posexponent > 0)
{
queuenumber = 2047 - exponent;
}
else
{
queuenumber = 2048 + exponent;
}
// Are we inserting into an empty queue?
if (queuefront[queuenumber] == null)
{
// Yes, we are inserting into an empty queue.
// Will this become the highest-priority queue?
if (queuenumber > firstnonemptyq)
{
// Yes, this is the highest-priority queue.
nextnonemptyq[queuenumber] = firstnonemptyq;
firstnonemptyq = queuenumber;
}
else
{
// No, this is not the highest-priority queue.
// Find the queue with next higher priority.
i = queuenumber + 1;
while (queuefront[i] == null)
{
i++;
}
// Mark the newly nonempty queue as following a higher-priority queue.
nextnonemptyq[queuenumber] = nextnonemptyq[i];
nextnonemptyq[i] = queuenumber;
}
// Put the bad triangle at the beginning of the (empty) queue.
queuefront[queuenumber] = badtri;
}
else
{
// Add the bad triangle to the end of an already nonempty queue.
queuetail[queuenumber].next = badtri;
}
// Maintain a pointer to the last triangle of the queue.
queuetail[queuenumber] = badtri;
// Newly enqueued bad triangle has no successor in the queue.
badtri.next = null;
}
/// <summary>
/// Add a bad triangle to the end of a queue.
/// </summary>
/// <param name="enqtri"></param>
/// <param name="minedge"></param>
/// <param name="apex"></param>
/// <param name="org"></param>
/// <param name="dest"></param>
public void Enqueue(ref Otri enqtri, double minedge, Vertex apex, Vertex org, Vertex dest)
{
// Allocate space for the bad triangle.
BadTriangle newbad = new BadTriangle();
newbad.poortri = enqtri;
newbad.key = minedge;
newbad.apex = apex;
newbad.org = org;
newbad.dest = dest;
Enqueue(newbad);
}
