Example #1
0
        public void Push(Object item)
        {
            var node = new Node((int)item);

            node.Next = top;
            top = node;
        }
 // Initializes the LL with a head
 public DoublyLinkedList(int val)
 {
     head = new Node(val);
     head.next = null;
     head.prev = null;
     tail = head;
 }
 private void InsertAtHead(int value)
 {
     if(IsEmpty())
     {
         var node = new Node(value);
         _head = node;
         _tail = node;
     }
 }
 public void Have_Ability_To_Add_To_Head_Or_Tail_Node()
 {
     LinkedList<int> list = new LinkedList<int>();
     Node<int> headNode = new Node<int>(100);
     Node<int> tailNode = new Node<int>(200);
     list.AddToHead(headNode);
     list.AddToTail(tailNode);
     Assert.AreSame(headNode, list.Head);
     Assert.AreSame(tailNode, list.Tail);
 }
Example #5
0
        public void Have_A_Pointer_To_Next_Node()
        {
            Node<int> nodeA = new Node<int>();
            nodeA.Value = 100;

            Node<int> nodeB = new Node<int>();
            nodeB.Value = 200;
            nodeA.Next = nodeB;

            Assert.AreSame(nodeB, nodeA.Next);
        }
Example #6
0
        public Object Pop()
        {
            if (top != null)
            {
                Object item = top.Data;
                top = top.Next;

                return item;
            }

            return null;
        }
Example #7
0
 public void Add(int value)
 {
     if (ReferenceEquals(First, null))
         First = new Node { Value = value };
     else
     {
         var current = First;
         while (!ReferenceEquals(current.Next, null))
             current = current.Next;
         current.Next = new Node { Value = value };
     }
     Count++;
 }
Example #8
0
 public void Push(int value)
 {
     if (_node == null)
     {
         _node = new Node(value);
     }
     else
     {
         var newNode = new Node(value);
         newNode.SetNextNode(_node);
         _node = newNode;
     }
 }
Example #9
0
 public void Enqueue(Object item)
 {
     if (_first == null)
     {
         _last = new Node((int)item);
         _first = _last;
     }
     else
     {
         _last.Next = new Node((int)item);
         _last = _last.Next;
     }
 }
Example #10
0
        public static HashTable<char, BitStream> MakeEncodingTable(Node node, BitStream progress)
        {
            HashTable<char,BitStream> result = new HashTable<char,BitStream>(char.MaxValue,HashChar);

            //if the current node is not null and it is a leaf, we want to add it to result
            if (node != null && node.Left == null && node.Right == null) {
                //we only store leaf nodes in the result array
                //make a new bit stream
                BitStream stream = new BitStream();
                //append progress to it
                stream.Append(progress);
                //add node.data and the new stream to result
                result.Add(node.Data, stream);
            }

            //else if the node is not null, we are going to want to process it's childern
            else {
                if (node != null && node.Left != null) {
                    //if left subtree is not null
                    //make new bit stream
                    BitStream stream = new BitStream();
                    //append progress
                    stream.Append(progress);
                    //append 0 (because we are going left)
                    stream.Append(false);
                    //recursivley call this function on node.Left with the new stream we just created
                    //store the result of the previous call in a local hashtable
                    HashTable<char, BitStream> local = MakeEncodingTable(node.Left, stream);
                    //loop through the just created hash table(the return of the recursive function)
                    SLinkedList<char> list = local.Keys;
                    for (int i = 0; i < list.Size; i++) {
                        //add each key value pair to this function's result hash table
                        result.Add(list[i], local[list[i]]);
                        //we do this because the results of each recursion bubble back up to the top.
                        //by the time the root returns, all of the leaf nodes will be in the final hash table
                    }//end loop
                }//end if
                if (node != null && node.Right != null) {
                    //repeat above for the right subtree
                    BitStream stream = new BitStream();
                    stream.Append(progress);
                    stream.Append(true);
                    HashTable<char, BitStream> local = MakeEncodingTable(node.Right, stream);
                    SLinkedList<char> list = local.Keys;
                    for (int i = 0; i < list.Size; i++) {
                        result.Add(list[i], local[list[i]]);
                    }
                }//end else
            }
            return result;
        }
 public void Have_Count_Of_Current_Items()
 {
     LinkedList<int> list = new LinkedList<int>();
     Node<int> node100 = new Node<int>(100);
     Node<int> node200 = new Node<int>(200);
     Node<int> node300 = new Node<int>(300);
     Assert.AreEqual(0, list.Count);
     list.AddToTail(node100);
     Assert.AreEqual(1, list.Count);
     list.AddToTail(node200);
     Assert.AreEqual(2, list.Count);
     list.AddToTail(node300);
     Assert.AreEqual(3, list.Count);
 }
Example #12
0
        // Compares by Length, Height, and W<idth.

        public int CompareTo(DataStructures.Node a, DataStructures.Node b)
        {
            if (a.Value > b.Value)
            {
                return(1);
            }
            else if (a.Value < b.Value)
            {
                return(-1);
            }
            else
            {
                return(0);
            }
        }
 public void Have_Ability_To_Remove_Head_Or_Tail_Node()
 {
     LinkedList<int> list = new LinkedList<int>();
     Node<int> node100 = new Node<int>(100);
     Node<int> node200 = new Node<int>(200);
     Node<int> node300 = new Node<int>(300);
     list.AddToTail(node100);
     list.AddToTail(node200);
     list.AddToTail(node300);
     Assert.AreSame(node100, list.Head);
     list.RemoveFromHead();
     Assert.AreSame(node200, list.Head);
     Assert.AreSame(node300, list.Tail);
     list.RemoveFromTail();
     Assert.AreSame(node200, list.Tail);
 }
Example #14
0
        public Object Dequeue()
        {
            if (_first != null)
            {
                Object item = _first.Data;
                _first = _first.Next;

                if (_first == null)
                {
                    // Queue is empty
                    _last = null;
                }

                return item;
            }

            return null;
        }
 // Adds a new node to the tail of the LL
 // O(n) time
 public void Append(int val)
 {
     if (tail == null)
     {
         head = new Node(val);
         tail = head;
         return;
     }
     if (head == tail)
     {
         tail = new Node(val);
         tail.prev = head;
         head.next = tail;
         return;
     }
     var newTail = new Node(val);
     tail.next = newTail;
     newTail.next = null;
     newTail.prev = tail;
     tail = newTail;
 }
        // Searches LL for the first occurence of a node with val = val, and removes it
        // O(n) time
        // Post: val if node was found and deleted, -1 if no such node with val = val exists
        public int Delete(int val)
        {
            Node current = head;
            Node previous = null;

            while (current != null)
            {
                if (current.val == val)
                {
                    if (previous == null) // at head
                    {
                        head = current.next;
                        if (head != null)
                        {
                            head.prev = null;
                        }
                    }
                    else
                    {
                        if (current.next == null) // at tail
                        {
                            current.prev.next = null;
                            tail = current;
                        }
                        else
                        {
                            current.prev.next = current.next;
                            current.next.prev = current.prev;
                        }
                    }
                    return val;
                }
                previous = current;
                current = current.next;
            }
            return -1;
        }
Example #17
0
 public NodeList(Node node)
     : base(node)
 {
 }
        // Traverses the LL from the head to the specified index and removes the node
        // O(n) time
        // Post: node's val if node was found and deleted, -1 if no such node at index = index exists
        public int DeleteAt(int index)
        {
            if (index < 0)
            {
                return -1;
            }
            int currIndex = 0;
            Node current = head;
            Node previous = null;

            while (current != null)
            {
                if (currIndex == index)
                {
                    int nodeVal;
                    if (previous == null) // at head
                    {
                        if (current == tail)
                        {
                            head = null;
                            tail = null;
                            return index;
                        }
                        nodeVal = head.val;
                        head = current.next;
                        if (head != null)
                        {
                            head.prev = null;
                        }
                    }
                    else
                    {
                        if (current.next == null) // at tail
                        {
                            current.prev.next = null;
                            tail = current;
                        }
                        else
                        {
                            current.prev.next = current.next;
                            current.next.prev = current.prev;
                        }
                        nodeVal = current.val;
                    }
                    return nodeVal;
                }
                previous = current;
                current = current.next;
                currIndex++;
            }
            return -1;
        }
 // Helper - Inits the doubly linked list with values 5 to 0, head to tail
 public void InitializeDLL()
 {
     this.head = null;
     for (int i = 0; i < 6; i++)
     {
         Push(i);
     }
 }
Example #20
0
        public static Node MakeHuffmanTree(HashTable<char, int> frequencyTable)
        {
            //First, create a singly linked list of nodes to return
            SLinkedList<Node> looseNodes = new SLinkedList<Node>();
            //we need to loop through the given frequency table
            SLinkedList<char> keys = frequencyTable.Keys;
            for (int i = 0; i < keys.Size; i++) {
                //make new node for each element in hash table
                Node n = new Node();
                //node Data is current key (keys[i])
                n.Data = keys[i];
                //node frequency is going to be the value for the current key (table[key])
                n.Frequency = frequencyTable[keys[i]];
                //add this new node to the end(tail) of the loose nodes list
                looseNodes.AddTail(n);
            }//end loop

            /* Comments, no code */
            // Next we need to take this loose collection of nodes and build a tree out of it.
            // We do this by combining the smallest value nodes under a parent node. Each iteration
            // Of the below loop will reduce size by 1, because it removes two nodes and adds one.
            // We know we have a tree built, when the loose nodes list has a size of 1.
            /* End comments */

            //loop while the looseNodes list has more than one element in it
            while (looseNodes.Size > 1) {
                //make local variable called left and set it to looseNodes[0]
                Node left = looseNodes[0];
                //we want to set left to the lowest frequency node, loop through nodes
                for (int i = 0; i < looseNodes.Size; i++) {
                    //if frequency of current node is less than left
                    if (left.Frequency > looseNodes[i].Frequency) {
                        //set left to current node
                        left = looseNodes[i];
                    }//end if
                }//end loop
                //now that we have a  reference to the smallest node, lets remove it from the list
                looseNodes.RemoveAt(looseNodes.IndexOf(left));
                //Repeat above steps for a new local node called right
                Node right = looseNodes[0];
                for (int i = 0; i < looseNodes.Size; i++) {
                    if (right.Frequency > looseNodes[i].Frequency) {
                        right = looseNodes[i];
                    }
                }
                looseNodes.RemoveAt(looseNodes.IndexOf(right));
                //Make a new node
                Node n = new Node();
                //set its left to the local left node
                n.Left = right;
                //set its right to the local right node
                n.Right = left;
                //set its frequency to the sum of the left and right nodes frequencies
                n.Frequency = right.Frequency + left.Frequency;
                //set its data to '\0' (char equivalent of null)
                n.Data = '\0';
                //Add the new node to the end of the looseNodes list(AddTail)
                looseNodes.AddTail(n);
            }//end loop
            //at this point the loose node list has only one element, and it's the root node of our huffman table
            //return [0] of the loose list
            return looseNodes[0];
            //end loop ?? what loop
        }
Example #21
0
 public void Have_A_Value()
 {
     Node<int> node = new Node<int>();
     node.Value = 100;
     Assert.AreEqual(100, node.Value);
 }
        // Removes the tail from the LL
        // O(1) time
        public int Pop()
        {
            if (tail == null)
            {
                throw new Exception("Cannot pop from an empty Linked List!");
            }
            int tailVal;

            if (head == tail)
            {
                tailVal = tail.val;
                head = null;
                tail = null;
                return tailVal;
            }

            tailVal = tail.val;
            tail = tail.prev;
            tail.next = null;
            return tailVal;
        }
        // Adds a new node to the head of the LL
        // O(1) time
        public void Push(int val)
        {
            if (head == null) // new head and tail
            {
                head = new Node(val);
                tail = head;
                return;
            }

            if (head.next == null) // head becomes tail
            {
                tail = new Node(head.val);
                tail.prev = head;
                tail.next = null;
                head.next = tail;
                head.val = val;
                return;
            }

            var oldHead = new Node(head.val); // just a new head
            oldHead.next = head.next;
            oldHead.prev = head;
            head.next.prev = oldHead;
            head.val = val;
            head.next = oldHead;
        }
Example #24
0
 public Node(Node node)
 {
     Data = node.Data;
 }
Example #25
0
 public NodeTree(Node node)
     : base(node)
 {
 }
Example #26
0
 public void SetPrevious(Node node)
 {
     if (_previousNode == null)
     {
         _previousNode = node;
         _previousNode.SetNextNode(this);
     }
 }
Example #27
0
 public void SetAt(int index, Node element)
 {
     if (!IsWithinBounds(index)) return;
     if (index == 0)
     {
         if (ReferenceEquals(element, null))
         {
             First = First.Next;
             Count--;
         }
         else
         {
             element.Next = First.Next;
             First = element;
         }
     }
     else
     {
         var current = First;
         for (int i = 0; i < index - 1; i++)
             current = current.Next;
         if (ReferenceEquals(element, null))
         {
             current.Next = current.Next.Next;
             Count--;
         }
         else
         {
             element.Next = current.Next.Next;
             current.Next = element;
         }
     }
 }