// TODO: Move these code to a statcic class EulerianCycleTestHelper
/**************************************************************************
*
* The code below is solely for testing correctness of the data type.
*
**************************************************************************/
// Determines whether a graph has an Eulerian cycle using necessary
// and sufficient conditions (without computing the cycle itself):
// - at least one edge
// - degree(v) is even for every vertex v
// - the graph is connected (ignoring isolated vertices)
private static bool hasEulerianCycle(Graph G)
{
// Condition 0: at least 1 edge
if (G.E == 0)
{
return(false);
}
// Condition 1: degree(v) is even for every vertex
for (int v = 0; v < G.V; v++)
{
if (G.Degree(v) % 2 != 0)
{
return(false);
}
}
// Condition 2: graph is connected, ignoring isolated vertices
int s = nonIsolatedVertex(G);
BreadthFirstPaths bfs = new BreadthFirstPaths(G, s);
for (int v = 0; v < G.V; v++)
{
if (G.Degree(v) > 0 && !bfs.HasPathTo(v))
{
return(false);
}
}
return(true);
}
public static void MainTest(string[] args)
{
TextInput input = new TextInput(args[0]);
Graph G = new Graph(input);
int s = int.Parse(args[1]);
BreadthFirstPaths bfs = new BreadthFirstPaths(G, s);
for (int v = 0; v < G.V; v++)
{
if (bfs.HasPathTo(v))
{
Console.Write("{0} to {1} ({2}): ", s, v, bfs.DistTo(v));
foreach (int x in bfs.PathTo(v))
{
if (x == s)
{
Console.Write(x);
}
else
{
Console.Write("-" + x);
}
}
Console.WriteLine();
}
else
{
Console.Write("{0} to {1} (-): not connected\n", s, v);
}
}
}
/**************************************************************************
*
* The code below is solely for testing correctness of the data type.
*
**************************************************************************/
// Determines whether a digraph has an Eulerian path using necessary
// and sufficient conditions (without computing the path itself):
// - indegree(v) = outdegree(v) for every vertex,
// except one vertex v may have outdegree(v) = indegree(v) + 1
// (and one vertex v may have indegree(v) = outdegree(v) + 1)
// - the graph is connected, when viewed as an undirected graph
// (ignoring isolated vertices)
// This method is solely for unit testing.
private static bool hasEulerianPath(Digraph G)
{
if (G.E == 0)
{
return(true);
}
// Condition 1: indegree(v) == outdegree(v) for every vertex,
// except one vertex may have outdegree(v) = indegree(v) + 1
int deficit = 0;
for (int v = 0; v < G.V; v++)
{
if (G.Outdegree(v) > G.Indegree(v))
{
deficit += (G.Outdegree(v) - G.Indegree(v));
}
}
if (deficit > 1)
{
return(false);
}
// Condition 2: graph is connected, ignoring isolated vertices
Graph H = new Graph(G.V);
for (int v = 0; v < G.V; v++)
{
foreach (int w in G.Adj(v))
{
H.AddEdge(v, w);
}
}
// check that all non-isolated vertices are connected
int s = nonIsolatedVertex(G);
BreadthFirstPaths bfs = new BreadthFirstPaths(H, s);
for (int v = 0; v < G.V; v++)
{
if (H.Degree(v) > 0 && !bfs.HasPathTo(v))
{
return(false);
}
}
return(true);
}
public static void MainTest(string[] args)
{
string filename = args[0];
string delimiter = args[1];
string source = args[2];
SymbolGraph sg = new SymbolGraph(filename, delimiter);
Graph G = sg.G;
if (!sg.Contains(source))
{
Console.WriteLine(source + " not in database.");
return;
}
int s = sg.Index(source);
BreadthFirstPaths bfs = new BreadthFirstPaths(G, s);
TextInput StdIn = new TextInput();
while (!StdIn.IsEmpty)
{
string sink = StdIn.ReadLine();
if (sg.Contains(sink))
{
int t = sg.Index(sink);
if (bfs.HasPathTo(t))
{
foreach (int v in bfs.PathTo(t))
{
Console.WriteLine(" " + sg.Name(v));
}
}
else
{
Console.WriteLine("Not connected");
}
}
else
{
Console.WriteLine(" Not in database.");
}
}
}
/**************************************************************************
*
* The code below is solely for testing correctness of the data type.
*
**************************************************************************/
// Determines whether a digraph has an Eulerian cycle using necessary
// and sufficient conditions (without computing the cycle itself):
// - at least one edge
// - indegree(v) = outdegree(v) for every vertex
// - the graph is connected, when viewed as an undirected graph
// (ignoring isolated vertices)
private static bool hasEulerianCycle(Digraph G)
{
// Condition 0: at least 1 edge
if (G.E == 0)
{
return(false);
}
// Condition 1: indegree(v) == outdegree(v) for every vertex
for (int v = 0; v < G.V; v++)
{
if (G.Outdegree(v) != G.Indegree(v))
{
return(false);
}
}
// Condition 2: graph is connected, ignoring isolated vertices
Graph H = new Graph(G.V);
for (int v = 0; v < G.V; v++)
{
foreach (int w in G.Adj(v))
{
H.AddEdge(v, w);
}
}
// check that all non-isolated vertices are conneted
int s = nonIsolatedVertex(G);
BreadthFirstPaths bfs = new BreadthFirstPaths(H, s);
for (int v = 0; v < G.V; v++)
{
if (H.Degree(v) > 0 && !bfs.HasPathTo(v))
{
return(false);
}
}
return(true);
}
// TODO: Move these code to a statcic class EulerianCycleTestHelper
/**************************************************************************
*
* The code below is solely for testing correctness of the data type.
*
**************************************************************************/
// Determines whether a graph has an Eulerian path using necessary
// and sufficient conditions (without computing the path itself):
// - degree(v) is even for every vertex, except for possibly two
// - the graph is connected (ignoring isolated vertices)
// This method is solely for unit testing.
private static bool hasEulerianPath(Graph G)
{
if (G.E == 0)
{
return(true);
}
// Condition 1: degree(v) is even except for possibly two
int oddDegreeVertices = 0;
for (int v = 0; v < G.V; v++)
{
if (G.Degree(v) % 2 != 0)
{
oddDegreeVertices++;
}
}
if (oddDegreeVertices > 2)
{
return(false);
}
// Condition 2: graph is connected, ignoring isolated vertices
int s = nonIsolatedVertex(G);
BreadthFirstPaths bfs = new BreadthFirstPaths(G, s);
for (int v = 0; v < G.V; v++)
{
if (G.Degree(v) > 0 && !bfs.HasPathTo(v))
{
return(false);
}
}
return(true);
}